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3 years ago

Eyeglasses provide as much protection as safety goggles. * true or false

Chemistry

2 answers:

Artyom0805 [142]3 years ago

7 0

False. Eyeglasses do not cover all around the eye however safety goggles do

padilas [110]3 years ago

4 0

Answer:

false

Explanation:

because they eyeglasses don't go as close to the eyes as safety goggles

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g Suppose a 49. L reaction vessel is filled with 1.5 mol of NO. What can you say about the composition of the mixture in the ves

irakobra [83]

The question is incomplete, the complete question is:

At a certain temperature, the equilibrium constant $K_{eq}$ for the following reaction is 0.74:

$NO_3(g)+NO(g)\rightleftharpoons 2NO_2(g)$

Suppose a 49.0 L reaction vessel is filled with 1.5 mol of $NO_3$ and 1.5 mol of NO. What can you say about the composition of the mixture in the vessel at equilibrium?

A. There will be very little $NO_3$ and NO.

B. There will be very little $NO_2$

C. Neither of the above is true.

<u>Answer:</u> The correct option is B. there will be very little $NO_2$

<u>Explanation:</u>

We are given:

Initial moles of $NO_3$ = 1.5 moles

Initial moles of NO = 1.5 moles

Volume of vessel = 49 L

As, moles of reactants and moles of products are equal, the volume term will not appear in the equilibrium constant expression.

Equilibrium constant for the reaction = 0.74

For the given chemical equation:

$NO_3(g)+NO(g)\rightleftharpoons 2NO_2(g)$

Initial: 1.5 1.5 -

At eqllm: 1.5-x 1.5-x 2x

The expression of equilibrium constant for the above reaction:

$K_{eq}=\frac{[NO_2]^2}{[NO_3]\times [NO]}$

Putting values in above equation, we get:

$0.74=\frac{(2x)^2}{(1.5-x)(1.5-x)}\\\\x=-1.13, 0.451$

Neglecting the negative value of equilibrium constant because concentration cannot be negative

Equilibrium concentration of $NO_3$ = (1.5 - x) = (1.5 - 0.451) = 1.049 moles

Equilibrium concentration of NO = (1.5 - x) = (1.5 - 0.451) = 1.049 moles

Equilibrium concentration of $NO_2$ = 2x = $(2\times 0.451)=0.902mol$

There are 3 possibilities:

If $K_{eq}$ , the reaction is reactant favored
If $K_{eq}>1$ , the reaction is product favored.
If $K_{eq}=1$ , the reaction is in equilibrium.

Here, the value of $K_{eq}=0.74$ , which is less than 1, therefore the reaction is reactant favored and we can say that there will be very little $NO_2$ .

Hence, the correct option is B. there will be very little $NO_2$

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2 years ago

Identify the true statements regarding α-1, 6 linkages in glycogen.A. The number of sites for enzymes action on a glycogen molec

kenny6666 [7]

Answer:

C. The reaction that forms α-1, 6 linkages is catalyzed by branching enzymes.

Explanation:

α-glucan branching enzyme which can also be called the Brancher enzyme or glycogen-branching enzyme is the enzyme responsible for the side chain reaction that attaches at carbon atom 6 of a glucose unit (an α-1,6-glycosidic bond).

This branching enzyme attaches a string of seven glucose units to the carbon at the C-6 position on the glucose unit, forming the α-1,6-glycosidic bond.

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3 years ago

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QveST [7]

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2 years ago

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In a pure metal, the electrons can be thought of as [ Select ] throughout the metal. Using molecular orbital theory, there [ Sel

Phoenix [80]

Answer:

Explanation:

In a pure metal, the electrons can be thought of as [concentrated] around atoms throughout the metal. Using molecular orbital theory, there [is ] an energy gap between the filled molecular orbitals and empty molecular orbitals. The [antibonding] orbitals are typically higher in energy and are mostly (filled]

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2 years ago

Ice melts after adding heat. The free energy is ————— !

katovenus [111]

Answer: F. Endothermic…………………

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3 years ago