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Burka [1]
3 years ago
9

HELP!

Mathematics
1 answer:
Usimov [2.4K]3 years ago
5 0

Answer:

$0.50x+5=30

Step-by-step explanation:

maf

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Square root of 16 over 121
yawa3891 [41]
\sqrt{ \frac{16}{121} } = \sqrt{( \frac{4}{11})^{2} } =| \frac{4}{11}|= \frac{4}{11}

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<em>"Associate with people who are likely to improve you."</em>
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3 years ago
Ron recorded a temperature of 13°F, and Lexi recorded a temperature of 98°F. Who recorded a cooler temperature?
Leno4ka [110]
Ron because 13 is way colder than 98
8 0
3 years ago
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Scott has a rope 8 metres long. He says, “I need 9 pieces each 0.89 metres long.” Will Scott have enough ribbon? Explain your an
dybincka [34]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
Simplify 9 to the power of 2 over 9 to the power of 7 please help someone quick!
Charra [1.4K]

Answer:

1/59049

Step-by-step explanation:

4 0
3 years ago
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