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AlladinOne [14]
4 years ago
12

4y+8=8x+4 Solve for x and y

Mathematics
2 answers:
Natasha_Volkova [10]4 years ago
4 0
8x-4y= -8

2x-y=1
-Y=2x-1
Y=2x-1
WINSTONCH [101]4 years ago
3 0
4y=8x-4
Y=2x-1
Hope this is better
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Can someone help me to find length CD
uysha [10]

Answer:

CD = 3.602019190339

Step-by-step explanation:

CD = DA - CA

DA = DB×Cos(29) = 18.7×cos(29) = 16.355388523507

BA = BA×cos(43) = 18.7×cos(43) = 13.676314220278

CA = BA÷tan(47) = 13.676314220278÷tan(47) = 12.753369333168

Then

CD = 16.355388523507 - 12.753369333168 = 3.602019190339

7 0
4 years ago
I need the answer i don't know the answer so please help me
Alekssandra [29.7K]
1200 - 450 = 750 liters that he needs to fill up

81.5 x 750 = €61,125 
€61,125 x 0.075 = €4,584.38 (discount as a loyal customer)
total paid with discount = €61,125 - €4,584.38 = €56,540.62

answer
Mr. Leonard gets  €4,584.38 discount on his purchase
5 0
3 years ago
In a certain Algebra 2 class of 30 students, 14 of them play basketball and 10 of them play baseball. There are 14 students who
Veseljchak [2.6K]

Answer:

In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.

But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?

Thank you for all of the help.

That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)

So: the two events are not independent, and so that formula doesn't work.

Fortunately, a formula that does work (always!) is:

P(A∪B)=P(A)+P(B)−P(A∩B)

Hence:

P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330

7 0
3 years ago
What is the size of the matrix resulting from
kogti [31]

Answer:

1×3 or 3×3 I think...........

7 0
3 years ago
Read 2 more answers
The average home in the U.S. is expected to cost $240,000. A random sample of 65 homes sold this month showed an average price o
gulaghasi [49]

Solution :

It is given that we have a null and an alternative hypothesis. The hypothesis are :

$H_0: \mu = 240,000$

$H_a : \mu < 240,000$

We have to find if the cost of average home has decreased or not in this month.

So it is given that the test statics is -1.79, so the p value associated with the test statics is less than ( α ) 0.01

Therefore, we can conclude that the cost of the average house is less than $ 240,000.

8 0
4 years ago
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