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2 years ago

What is the percent of increase from $23 to $38?

Mathematics

1 answer:

Amiraneli [1.4K]2 years ago

3 0

The answer is 65.22%
Thank you !

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Ifthe fish commission states that the mean length of all fish in spring run is mean =15cm,withthe standard deviation of variance

Andrei [34K]

Answer:

Step-by-step explanation:

z(lower) = (15-15)/4 = 0

z(upper) = (19-15)/4= 1

z at 0 = .5

z at 1 = 0.841344746

(look these up in a Z table)

probability "between" = 0.841344746 - .5 = 0.3841344746

4 0

2 years ago

To the nearest tenth what is the length of the hypotenuse of a right triangle if one side measures 4.5meters and the other side

allsm [11]

Answer:

Step-by-step explanation:

c^2 = a^2 + b^2

4.5^2 + 9^2 = 101.25

c = sqrt 101.25 = 10.06 = 10.1 meters

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2 years ago

Bob needs to buy a cover for his above-ground pool. The pool is in the shape of a circle and has a diameter of 18 feet. Pool cov

EleoNora [17]

Answer:

13.5 dollar he should he expect

3 0

2 years ago

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Find out what make 30 with only the number 1,3,5,7,9,11,13,15

Mrrafil [7]

Answer:

Step-by-step explanation:

7 + 3 + 5 + 15 = 30

6 0

3 years ago

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Prove the trigonometric identity

Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

$1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1$

Lets solve the bottom most part first:

$1-\frac{1}{1-sec^2x} \\\\$

Take LCM

$1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}$

now break the LCM

$\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1$

because 1/tan = cot x

and furthermore,

$cot^2x+1\\cosec^2x$

now we solve the above part and replace the bottom most part that we solved with $cosec^2x$

$\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x$

Hence proved! :D

4 0

2 years ago