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goldfiish [28.3K]
3 years ago
11

Which choice correctly shows the solution(s) of the equation x2 = 625?

Mathematics
1 answer:
dybincka [34]3 years ago
7 0

Did you mean x^2? Then, the answer is x = +/- \sqrt{625}, which is +/- 25.

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Can someone help with this problem:)
Artyom0805 [142]

Answer:no

Step-by-step explanation:no

8 0
3 years ago
A bacteria culture starts with 880 bacteria and grows at a rate proportional to its size. after 5 hours there will be 4400 bacte
Alina [70]
Don't know whether or not you've encountered differential equations yet, but will try that approach here.

The growth rate is dy/dt  = ky (which states that the rate is proportional to the size of the population, y, and k is a constant.

Grouping like terms,  

dy
--- = kt, so y = Ne^kt
 y

We are told that at t=0, there are 880 bacteria.  Thus, 880=N.  Therefore,

y = 880e^(kt).  After 5 hours the pop will be 4400; using this info, find k:

4400=880e^(5k), or 5 = e^(5k).    So, our y = 880e^(kt) becomes

                                                                   y = 880e^(5t).

What will be the pop after 2 hours?           y(2)=880e^(10) = 880(22026) =
                                                                   approx. 19,383,290 bacteria

Time to reach a pop of 2550?  2550 = 880e^(5t).  Find t.

ln 2550 = ln 880 + 5t, so ln 2550 - ln 880 = 5t.  Divide both sides by 5 to obtain this time, t.
8 0
3 years ago
Write a polynomial function with the given zeros. multiply the terms (write in standard form).
ryzh [129]

1) \ f(x)=x^3-3x-2 \\ \\ 2) \ g(x)=x^3-x^2-6x

<h2>Explanation:</h2>

A \ \mathbf{polynomial \ function} \ of \ x \ with \ degree \ n \ is \ given \ by:\\ \\ f(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\ldots +a_{2}x^{2}+a_{1}x+a_{0} \\ \\ where \ n \ is \ a \ nonnegative \ integer \ and \ a_{n}, a_{n-1}, \ldots a_{2}, a_{1}, a_{0} \\ with \ a_{n}\neq 0

In this exercise, we have two cases and both will be polynomial functions with degree 3 because we have three real roots in each case. So:

<h3>First.</h3>

The roots are:

x= -1, -1, 2

So we can write this polynomial functions as the product of linear factors:

f(x)=(x-(-1))(x-(-1))(x-2) \\ \\ f(x)=(x+1)^2(x-2)

Since we have to write it in standard form, let's expand:

f(x)=(x+1)^2(x-2) \\ \\ \\ By \ property: \\ \\ (a+b)^2=a^2+2ab+b^2 \\ \\ \\ f(x)=(x^2+2x+1)(x-2) \\ \\ f(x)=x^3+2x^2+x-2x^2-4x-2 \\ \\ \\ Combine \ like \ terms: \\ \\ x^3+(2x^2-2x^2)+(x-4x)-2 \\ \\ \\ \boxed{f(x)=x^3-3x-2}

<h3>Second.</h3>

The roots are:

x= -2, 0, 3

Writing the polynomial function as the product of linear factors:

g(x)=(x-(-2))(x-0)(x-3) \\ \\ g(x)=(x+2)x(x-3) \\ \\ g(x)=x(x+2)(x-3) \\ \\ \\ Distributive \property: \\ \\ g(x)=x(x^2-3x+2x-6) \\ \\ g(x)=x(x^2-x-6) \\ \\ \\ Distributive \ property \ again: \\ \\ \boxed{g(x)=x^3-x^2-6x}

<h2>Learn more:</h2>

Degree of polynomial functions: brainly.com/question/5451252

#LearnWithBrainly

7 0
3 years ago
Read 2 more answers
I need help with this
wariber [46]
I’m not really sure, maybe try to combine common facts like x with the xs and numbers with numbers
3 0
3 years ago
A transformation T: (x, y) (x - 5, y + 3).
telo118 [61]

A' ( - 3, 2 ) that is B

a translation ( x - 5, y + 3 ) means subtract 5 from the x- coordinate and add 3 to the y-coordinate 3

A(2, - 1 ) → A'(2 - 5, - 1 + 3 ) → A'( - 3, 2 )


6 0
3 years ago
Read 2 more answers
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