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Reptile [31]
3 years ago
7

2/11 , 8/15, 7/13, 5/12 Which fraction does not belong with the other three?

Mathematics
1 answer:
ololo11 [35]3 years ago
3 0
It's 2/11 because all the others round to 1/2.
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What is the remainder of 245÷32
OverLord2011 [107]
It is 7.7 because u need to round it to the neares but not everytime;)
Brainestt??;)
7 0
4 years ago
Read 2 more answers
Line AC and line DB intersect at point P. Solve for angle BPQ.
taurus [48]

Answer:

Angle BPQ = 64°

Step-by-step explanation:

4x + 12 +2x = 90

6x + 12 = 90

     - 12    -12

6x = 78

x = 13°

BPQ = ((4(13) + 12)°

           (52 + 12)°

            64°

8 0
3 years ago
A Family purchased tickets to the movies in spent a total of $40.75. The family purchase five tickets there was a $.90 processi
muminat

Answer:

$7.25

Step-by-step explanation:

Total amount spent on the ticket   = $40.75

Number of ticket purchased  = 5

Processing fee per ticket  = $0.90

Unknown:

Cost of each ticket = ?

Solution:

To solve this problem, we need to find the processing fee for the 5 tickets purchase;

      Processing fee = number ticket x processing fee per ticket

      Processing fee  = 5 x 0.9  = $4.5

Now, the real cost a ticket = $40.75  - $4.5  = $36.25

So, cost per ticket is;

        Cost  = \frac{36.25}{5}   = $7.25

7 0
3 years ago
Assume that when adults with smartphones are randomly​ selected, 51​% use them in meetings or classes. If 11 adult smartphone us
Luba_88 [7]

Answer:

The probability is 0.2356.

Step-by-step explanation:

Let X is the event of using the smartphone in meetings or classes,

Given,

The probability of using the smartphone in meetings or classes, p = 51 % = 0.51,

So, the probability of not using smartphone in meetings or classes, q = 1 - p = 1 - 0.51 = 0.49,

Thus, the probability that fewer than 5 of them use their smartphones in meetings or classes.

P(X<5) = P(X=0) + P(X=1) + P(X=2) + P(X=3)+P(X=4)

Since, binomial distribution formula is,

P(x) = ^nC_r p^x q^{n-x}

Where, ^nC_r=\frac{n!}{r!(n-r)!}

Here, n = 11,

Hence,  the probability that fewer than 5 of them use their smartphones in meetings or classes

=^{11}C_0 (0.5)^0 0.49^{11}+^{11}C_1 (0.5)^1 0.49^{10}+^{11}C_2 (0.5)^2 0.49^{9}+^{11}C_3 (0.5)^3 0.49^{8}+^{11}C_4 (0.5)^4 0.49^{7}

=(0.5)^0 0.49^{11}+11(0.5)0.49^{10} + 55(0.5)^2 0.49^{9}+165 (0.5)^3 0.49^{8} +330(0.5)^4 0.49^{7}

=0.235596671797

\approx 0.2356

4 0
4 years ago
Help me please…………………….
givi [52]

Answer:

8.7

Step-by-step explanation:

If you like my answer mark me brainliest

5 0
3 years ago
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