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Sonbull [250]
3 years ago
11

Erik and Nita are playing a game with numbers. In the game, they each think of a random number from zero to 20. If the differenc

e between their two numbers is less than 10, then Erik wins. If the difference between their two numbers is greater than 10, then Nita wins. I pick Erik won and they asked,Use your previous answers to write an algebraic statement that represents all the ways your player will win. Be sure to define your variable
Mathematics
2 answers:
DanielleElmas [232]3 years ago
8 0
So erik is x and nita is y
x-y<10 or y-x<10
because if erik picks 11 then 11-y has to be less than 10 so nita would pick any number greater  than one and if nita picks12 then 12-x has to be less than 10 so erik would have to choose a number greater than two
Luda [366]3 years ago
5 0

Erik-   |x-y|<10

Nita-    |x-y|>10

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Valerie shares some of the 12 candies from this box.she gives her friend 1 candy for every 3 candies she eats herself. How many
True [87]

Answer:

3

Step-by-step explanation:

Every group of candies eaten is 4 candies because Valerie eats 3 and her friend eats 1. 1+3 = 4 . 12/4 = 3

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3 years ago
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If I counted correctly, the answer would be 52/150. You just need to simplify the fraction. I'll recount soon, and update if it changes.
3 0
3 years ago
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According to the University of Nevada Center for Logistics Management, 6% of all mer-
Fudgin [204]

Answer:

a) The point estimate of the proportion of items returned for the population of

sales transactions at the Houston store = 12/80 = 0.15

b) The 95% confidence interval for the proportion of returns at the Houston store = [0.0718 < p < 0.2282].

c) Yes.

We set an hypothesis and construct a test statistics. The test statistics result gives us:

Z calculated  = 2.2545, and this gives us the p-value = 0.0121. We assumed 95% confident interval. Hence, the level of significance (α) = 5%. Conclusively, since the p-value ==> 0.0121 is less than (α) = 5%, the test is significant. Hence, the proportion of returns at the Houston store is significantly different from the returns  for the nation as a whole.

Step-by-step explanation:

a) Point estimate of the proportion = number of returned items/ total items sold = 12/80 = 0.15.

b) By formula of confident interval:

CI(95%) = p ± Z*\sqrt{\frac{p*(1-p)}{n} }  =  0.15 \pm 1.96 *\sqrt{\frac{0.15*(1-0.15)}{80} },

CI(95%) = [0.0718 < p < 0.2282]

c) The hypothesis:

H_{0}: The proportion of returns at the Houston store is not significantly different from the returns  for the nation as a whole.

H_{a}: The proportion of returns at the Houston store is significantly different from the returns  for the nation as a whole.

The test statistics:

Z = \frac{\hat{p} - p_{0}}{\sqrt{\frac{p*(1-p)}{n} }}, where p_{0} is the proportion of nation returns.

Z calculated  = 2.2545, and this gives us the p-value = 0.0121. We assumed 95% confident interval. Hence, the level of significance (α) = 5%. Conclusively, since the p-value ==> 0.0121 is less than (α) = 5%, the test is significant. Hence, the proportion of returns at the Houston store is significantly different from the returns  for the nation as a whole.

6 0
3 years ago
Evan runs a website that has gotten quite popular. However, its popularity seems to be decreasing and the site is now getting 7%
anyanavicka [17]

Answer:

(a-b) *(a-b) *(a-b)

=(a*a*a) -3*(a*a*b)+3*(a*b*b)-(b*b*b)

34000*(1-7%)*(1-7%)*(1-7%)

=34000*(1-0.07)*(1-0.07)*(1-0.07)

=34000*[(1*1*1)-3*(1*1*0.07)+3*(1*0.07*0.07)-(0.07*0.07*0.07)]

=34000*(1-0.21+0.0147-0.000343)

=34000*(0.804357)

=34*1000*(804.357/1000)

=34*804.357

=<u>27348.138</u>

<u>=</u><u>27348</u>

4 0
4 years ago
PLEASE someone help me on this<br> I would appreciate it.
Anton [14]
2x-y =3
multiply by 4
8x - 4y = 12
3x +4y = 10 (unchanged equation)
------------------add
11x = 22

answer is A. the first.
first equation multiplied by 4 then sum to get 11x = 22

3 0
4 years ago
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