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Len [333]
3 years ago
8

PLEASE HELP ME ANSWER! im so desperate bro !!

Mathematics
1 answer:
sergey [27]3 years ago
6 0

a)13

b) skewed

c) IQR

d)Sam's observation is correct

e)6.17

Step-by-step explanation:

Step 1 :

From the histogram we can infer that

0 to 2 texts has been sent by 1 student

2 to 4 texts has been sent by 3 student

4 to 6 texts has been sent by 4 student

6 to 8 texts has been sent by 4 student

8 to 10 texts has been sent by 5 student

Step 2:

a)

From step 1 , we can see that there are total of 17 students represented by the histogram

Step 3:

b)

This is a skewed histogram because we have all large values of students on the right of the histogram and smaller values on the left of the histogram.

In symmetrical histogram, there would be large values on the center and the smaller values on both sides.

Step 4:

c)

IQR would be better recommendation for this as this is a skewed histogram

Standard deviation would be recommended for a symmetrical histogram

Step 5:

d)

Total number of students is 17

Number of students who text between 8 to 10 messages is 5

Hence the students who text between 8 and 10 messages is 5/17

which is nearly 1/3 rd of the total students.

Hence Sam's observation is correct

Step 6:

e)

Mean amount of the texts = (1 * 3 + 3* 3 + 5*4 +7*4 + 9* 5) /17 = 6.17

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Kamila [148]
The answer is B -9/25.
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3 years ago
There are values of t so that sin t=.35 and cos t=.6
NISA [10]

Recall the fundamental rule of trig:

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So, there exists an angle t such that

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if and only if

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Working out the numbers, we get

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(0.6,0.35)=(\sin(t),\cos(t))

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Zina [86]

Answer:

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