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vredina [299]
3 years ago
15

Which app or website teaches java and phyton

Computers and Technology
1 answer:
aev [14]3 years ago
6 0

Microsoft is a website that teaches java and phyton

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User Interface

Explanation:

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Create pseudocode that could be used as a blueprint for a program that would do the following: An employer wants you to create a
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Answer:

START LOOP FOR EACH EMPLOYEE:

   INPUT employee’s name, hourly rate of pay, number of hours worked, overtime pay rate, payroll deductions, tax rate

   SET gross pay = (hourly rate of pay x *weekly hours) + (overtime pay rate x (number of hours worked - *weekly hours))

   PRINT gross pay

   SET net pay = gross pay - (payroll deductions + (gross pay * tax rate/100 ))

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END LOOP

* weekly hours (how many hours an employee needs to work to earn overtime pay rate) is not given in the question

Explanation:

Create a loop that iterates for each employee

Inside the loop, ask for name, hourly rate, number of hours worked, overtime pay rate, payroll deductions, tax rate. Calculate the gross pay and print it. Calculate the net pay and print it

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Get user input as a boolean and store it in the variable tallEnough. Also, get user input as a boolean and store it in the varia
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Answer:

I will code in JAVA.

import java.util.Scanner;

public class Main {

public static void main(String[] args) {

 

boolean tallEnough;

boolean oldEnough;

Scanner input = new Scanner(System.in);

tallEnough = input.nextBoolean();<em> //wait the input for tallEnough</em>

oldEnough = input.nextBoolean(); <em>//wait the input for OldEnough</em>

   if(tallEnough && oldEnough){

   System.out.print(true);

   } else {

   System.out.print(false);

   }

}

}

Explanation:

First, to accept user inputs you have to import the class Scanner. Then declare both variables before allowing the user to set input values for both boolean variables.

In the if-else statement checks if both variables are true, then prints true. Another case prints always false.

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