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geniusboy [140]
3 years ago
12

Which statement shows how the product of (x + 7)2 demonstrates the closure property of multiplication?

Mathematics
2 answers:
Illusion [34]3 years ago
7 0

<h3>(x + 7)² = x² + 14x + 49</h3>

The true statement that show the closure property of multiplication :

<h3>a.  x² + 14x + 49 is a polynomial</h3>

\texttt{ }

<h3>Further explanation</h3>

<em>If equation ax³ + bx² + cx + d = 0 has roots x₁ , x₂ , and x₃ then</em>

x_1 + x_2 + x_3 = - \frac{b}{a}

x_1 x_2 + x_1 x_3 + x_2 x_3 = \frac{c}{a}

x_1 x_2 x_3 = - \frac{d}{a}

Let us now tackle the problem!

\texttt{ }

This problem is about Polynomial.

(x + 7)^2 = (x + 7)(x + 7)

(x + 7)^2 = x^2 + 7x + 7x + 7(7)

(x + 7)^2 = x^2 + 14x + 49

x^2 + 14x + 49 is a polynomial.

x + 7 is polynomial.

It demonstrates the closure property of multiplication.

\texttt{ }

<h3>Conclusion:</h3>

<em>The true statement that show how the product of (x + 7)² demonstrates the closure property of multiplication:</em>

<h3>a.  x² + 14x + 49 is a polynomial</h3>

\texttt{ }

<h3>Learn more</h3>
  • Solving Quadratic Equations by Factoring : brainly.com/question/12182022
  • Determine the Discriminant : brainly.com/question/4600943
  • Formula of Quadratic Equations : brainly.com/question/3776858

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Polynomial

\texttt{ }

Keywords: Quadratic , Equation , Discriminant , Real , Number

#LearnWithBrainly

Tasya [4]3 years ago
7 0

answer:

a.  x2 + 14x + 49 is a polynomial

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