The trigonometric function that models the distance (feet) of the rider from the camera as a function of time (seconds) is γ(t) = ωt, where ω is the angular velocity of merry-go-round.
Let, center of the merry-go-round is C and camera is placed at point A. B(t) define the position of the rider at any time t. The angle between these three-point A, C and B is y(t). Radius (r) of the merry-go-round is 3 feet and distance (d) of the rider from the camera is 6 and the angular velocity of the rider is ω.
Assume the rider is at the edge of the merry-go-round (as the position is not specified). So, the length of CB(t) is r. To solve this problem lets consider that angular velocity of merry-go-round is constant, ω = 0 and y(t) = 0.
Therefore, we have y(t) = ωt
So, the the distance (feet) of the rider from the camera is (from the triangle AB(t)C)
C(t) = √(r² + d² - 2rdcos(y(t)) = √(45 - 36cos(ωt) = 3√(5 - 4cos(ωt))
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Answer:
The average sallary of a Master's is 60 thousand and of a Bachellor's is 53 thousand.
Step-by-step explanation:
In order to solve this problem we first need to attribute variables to the unkown quantities. We will call the average salary of Master's "x" and the average salary of a Bachellor's "y". The first information the problem gives us is:
x = 2*y - 46
The second one is:
x + y = 113
We now have two equations and two variables, so we can solve the system. To do that we will use the value for x from the first equation on the second one. We have:
2*y - 46 + y = 113
3*y = 113 + 46
3*y = 159
y = 159/3 = 53
x = 2*(53) - 46 = 60
The average sallary of a Master's is 60 thousand and of a Bachellor's is 53 thousand.
1. 37 degree. A triangle has 180 there is a right angle 90 and then c is 53 which leaves 37 for a
9514 1404 393
Answer:
19 players
Step-by-step explanation:
The total being spent is ...
bus cost + (per player cost) × (number of players) = total raised
250 + 25.85p = 741.15
25.85p = 491.15
p = 491.15/25.85 = 19
The team could bring 19 players to the tournament.