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3 years ago

-18/-32/41/8/-11 from least to greatest

Mathematics

2 answers:

dedylja [7]3 years ago

6 0

Answer:

The answer is -32, -18, -11, 8, 41.

Step-by-step explanation:

For negative number, the greater the number the smaller it is. For example, -2 is smaller than -1. ( -2 < -1 )

For positive number, the greater the number the larger it is. For example, 1 is smaller than 2. ( 1 < 2 )

Elodia [21]3 years ago

4 0

Answer:

-32, -18, -11, 8, 41

Step-by-step explanation:

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Which is the equation of the line with a slope 3 and y intercept 5

Bess [88]

<h3>Option A</h3><h3>3x - y = -5 is the equation of the line with a slope 3 and y intercept 5</h3>

<em><u>Solution:</u></em>

<em><u>The slope intercept form of equation is given as:</u></em>

y = mx + c ------ eqn 1

Where,

m is the slope of line

c is the y intercept

From given,

slope = m = 3

y intercept = c = 5

<em><u>Substitute m = 3 and c = 5 in eqn 1</u></em>

y = 3x + 5

3x - y = -5

Thus the equation of line is found

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3 years ago

A rental car company is running two specials. Customers can pay $40 to rent a compact car for the first day plus $6 for each add

Flura [38]

Answer: she wants to rent the car for 11 days.

Step-by-step explanation:

Let x represent the number of additional days that Pamela wants to rent the car for.

Customers can pay $40 to rent a compact car for the first day plus $6 for each additional day. This means that the total cost of using this special for x days would be

40 + 6(x - 1) = 40 + 6x - 6

= 34 + 6x

Also, they can rent the same car for $30 the first day and $7 for every additional day beyond that. This means that the total cost of using this special for x days would be

30 + 7(x - 1) = 30 + 7x - 7

= 23 + 7x

Since she found out that the two specials are equivalent for x days, then

34 + 6x = 23 + 7x

7x - 6x = 34 - 23

x = 11

4 0

3 years ago

Find thd <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D" id="TexFormula1" title="\frac{dy}{dx}" alt="\frac{dy}{dx}" a

NARA [144]

$x^3y^2+\sin(x\ln y)+e^{xy}=0$

Differentiate both sides, treating $y$ as a function of $x$ . Let's take it one term at a time.

Power, product and chain rules:

$\dfrac{\mathrm d(x^3y^2)}{\mathrm dx}=\dfrac{\mathrm d(x^3)}{\mathrm dx}y^2+x^3\dfrac{\mathrm d(y^2)}{\mathrm dx}$

$=3x^2y^2+x^3(2y)\dfrac{\mathrm dy}{\mathrm dx}$

$=3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}$

Product and chain rules:

$\dfrac{\mathrm d(\sin(x\ln y)}{\mathrm dx}=\cos(x\ln y)\dfrac{\mathrm d(x\ln y)}{\mathrm dx}$

$=\cos(x\ln y)\left(\dfrac{\mathrm d(x)}{\mathrm dx}\ln y+x\dfrac{\mathrm d(\ln y)}{\mathrm dx}\right)$

$=\cos(x\ln y)\left(\ln y+\dfrac1y\dfrac{\mathrm dy}{\mathrm dx}\right)$

$=\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}$

Product and chain rules:

$\dfrac{\mathrm d(e^{xy})}{\mathrm dx}=e^{xy}\dfrac{\mathrm d(xy)}{\mathrm dx}$

$=e^{xy}\left(\dfrac{\mathrm d(x)}{\mathrm dx}y+x\dfrac{\mathrm d(y)}{\mathrm dx}\right)$

$=e^{xy}\left(y+x\dfrac{\mathrm dy}{\mathrm dx}\right)$

$=ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}$

The derivative of 0 is, of course, 0. So we have, upon differentiating everything,

$3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}+\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}+ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}=0$

Isolate the derivative, and solve for it:

$\left(6x^3y+\dfrac{\cos(x\ln y)}y+xe^{xy}\right)\dfrac{\mathrm dy}{\mathrm dx}=-\left(3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}\right)$

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}}{6x^3y+\frac{\cos(x\ln y)}y+xe^{xy}}$

(See comment below; all the 6s should be 2s)

We can simplify this a bit by multiplying the numerator and denominator by $y$ to get rid of that fraction in the denominator.

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^3+y\cos(x\ln y)\ln y-y^2e^{xy}}{6x^3y^2+\cos(x\ln y)+xye^{xy}}$

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3 years ago

The points (1, 5) and (0, –2) fall on a particular line. What is its equation in slope-intercept form?

Savatey [412]

The equation of the line in slope intercept form is y = 7x - 2

<h3>How to find the equation of a line?</h3>

The equation of the line can be solved with the following equation.

y = mx + b

where

m = slope
b = y-intercept

Therefore,

m = -2 - 5 / 0 - 1 = -7 / -1

m = 7

Hence, using (1, 5)

y = 7x + b

5 = 7(1) + b

5 - 7 = b

b = -2

Therefore,

y = 7x - 2

Hence, the equation of the line in slope intercept form is y = 7x - 2

learn more on equation of a line here: brainly.com/question/14956513

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kari74 [83]

The answer would be $19 on eg

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