2 years ago

Write the standard equation for a circle with center (−6, −8), that passes through (0, 0)

1 answer:

7 0

Standard equation: (x-h)^2 + (y-k)^2 = r^2

Here, (0-[-6])^2 + (0-[-8])^2 = r^2
Find r: 36 + 64 = 100, so r = 10

Then the desired equation is (x+6)^2 + (y+8)^2 = 10^2

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Let p(x) = 7x + 5 and r(x) = x - 1. Find and evaluate (r x p) (5)

quester [9]

Answer: 39

Step-by-step explanation:

Given

P(x)=7x+5

r(x)=x-1

r(p(x))=7x+5-1=7x+4

so, r(p(5))

$\Rightarrow r(p(5))=7\times 5+4=35+4=39$

8 0

2 years ago

A positive integer is 1010 more than 2727 times another. their product is 1211712117. find the two integers.

Goshia [24]

1010 + 2727x = y
x*y = 1211712117
x*(1010 + 2727x) = 1211712117
2727x^2 + 1010x - 1211712117 = 0

Here's the nasty part.
In order for this to work, the square root of the quadratic formula must come back with an integer. In fact sqrt (b^2 - 4ac) comes back with
3635568.29 something. which is not a whole number. Either there is an error in the givens or something, but this question is never going to do what you think it will do.

4 0

2 years ago

What is 2and 2/3 divided by 4/5

Illusion [34]

Answer:

$\frac{10}{3}$