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riadik2000 [5.3K]
3 years ago
7

Write the standard equation for a circle with center (−6, −8), that passes through (0, 0)

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
7 0
Standard equation:  (x-h)^2 + (y-k)^2 = r^2

Here,                        (0-[-6])^2 + (0-[-8])^2 = r^2
Find r:                           36        +   64         = 100, so r = 10

Then the desired equation is (x+6)^2 + (y+8)^2 = 10^2
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