Option B
Trevor isn't correct because -2i must also be a root
<em><u>Solution:</u></em>
For the polynomial with roots -7, 2i and 7 their roots can be,
1. ) Real roots
2.) Imaginary roots
The real roots are: -7 and +7
The imaginary root given is: 2i
The imaginary roots come from the square root. So they will be in form of ![\pm 2i](https://tex.z-dn.net/?f=%5Cpm%202i)
Therefore,
For f(x) with roots -7 and +7 and
we have,
![f(x)=a(x+7)(x-7)(x-2i)(x+2i)](https://tex.z-dn.net/?f=f%28x%29%3Da%28x%2B7%29%28x-7%29%28x-2i%29%28x%2B2i%29)
Fundamental Theorem of Algebra states that a polynomial will have exactly as many roots as its degree (the degree is the highest exponent of the polynomial).
So for f(x) with 4 roots, degree of f(x) is 4
So option B is correct. Trevor is not correct because –2i must also be a root.
Answer:
Volume of cylinder rounded to nearest tenth is 3.14 cubic inches .
Step-by-step explanation:
60, because 30+90 is 120 and 180-120 is 60 and since that angel is the same as x, x=60
Answer:
1384.74cm squared
Step-by-step explanation:
A= πr²