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Brums [2.3K]
2 years ago
15

What is the constant of proportionality for the table? What does it represent? Reminder: k= y/x

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
3 0

Answer:

The constant of proportionality is 5. It represents the cups of yellow paint needed for 1 cup of blue paint.

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PLEASE HELP WILL MARK BRAINLIEST
bogdanovich [222]

Answer:

I believe the answer is 39.368, if we round that it makes it, 39.4

Step-by-step explanation:

5 0
2 years ago
Two equations are given below: a – 3b = 9 a = b – 3 What is the solution to the set of equations in the form (a, b)?
Vilka [71]
A-3b=9
a=b-3

b-3-3b=9
-2b-3=9
-2b=12
2b=-12
b=-6

a=-6-3
a=-9

Solution: (-9,-6)
----
Check: 
-9=-6-3
-9=-9
TRUE


7 0
3 years ago
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Pls check picture! Pls give me answer pls! ASAP Right answer. if you dont know dont answer pls!!!! Right Answer for brainliest!
lyudmila [28]

Answer: The answer is 6 and 4.

Step-by-step explanation:

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3 years ago
The measures of the angles between the resultant and two applied forces are 26° and
erma4kov [3.2K]

Answer:

  48.8 lbs

Step-by-step explanation:

The forces can be modeled by a triangle with acute angles 20° and 26°, and obtuse angle 134° opposite a side of length 80. The larger component force will be opposite the angle 26°, and can be found using the Law of Sines:

  a/sin(A) = c/sin(C)

  x/sin(26°) = 80/sin(134°)

  x = 80sin(26°)/sin(134°) ≈ 48.753 . . . . pounds

The larger component force is about 48.8 pounds.

6 0
1 year ago
Solve for x : log(3x) + log(x + 4) = log(15).<br><br>Please explain it to me.​
zlopas [31]

Answer:

x = 1

Explanation:

\sf \rightarrow log(3x) + log(x + 4) = log(15)

Rule: log(a) + log(b) = log(ab)

\sf \rightarrow log(3x(x + 4)) =  log(15)

cancel out log on both sides

\sf \rightarrow 3x(x + 4) = 15

relocate constant variable

\sf \rightarrow 3x^2 + 12x -15 = 0

take 3 as a common factor

\sf \rightarrow 3(x^2 + 4x -5) = 0

divide both sides by 3

\sf \rightarrow x^2 + 4x -5 = 0

middle term split

\sf \rightarrow x^2 + 5x -x-5 = 0

factor common terms

\sf \rightarrow x(x  + 5) -1(x+5)= 0

collect into groups

\sf \rightarrow (x-1)(x+5)= 0

set to zero

\sf \rightarrow x-1 = 0 , \ x+5= 0

relocate variables

\sf \rightarrow x = 1,  \ x = -5

There must be a positive solution for log, so the solution is only x = 1

3 0
1 year ago
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