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Over [174]
4 years ago
6

Obtain two numbers such their HCF is 20 and their LCM is 300....... By steps... ​Plzzzzzz answer fast​

Mathematics
1 answer:
kap26 [50]4 years ago
4 0

Answer:

60 and 100

Step-by-step explanation:

Look for 2 multiples of 20 which are also factors of 300.

No long explanation needed

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11.49 for 3 packages
Vera_Pavlovna [14]

Answer:

Individual package would be 3.83

Hope this helps <3 Comment if you want more thanks and be sure to give brainliest (4 left) <3

5 0
3 years ago
Help please this is due tonight
Natalija [7]

Answer:

x = 5

Step-by-step explanation:

Since the triangles have to be congruent (through SSS), we know that:

2x + 3 = 4x - 7

We simplify this to: 2x = 10

And then: x = 5

7 0
3 years ago
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a zoologist hides in a bush 200 feet away from a tree inhabited by a family of monkeys. if the zoologist is looking up at an ang
Nastasia [14]

Answer:

\displaystyle  53.6ft

Step-by-step explanation:

<u>refer</u><u> the</u><u> attachment</u>

let the height be h

since we are given the adjacent side and want to figure out opposite side we'll use tan function

so our equation is

\displaystyle  \tan( {15}^{ \circ} )  =  \frac{h}{200}

cross multiplication:

\displaystyle  h = 200\tan( {15}^{ \circ} )

by using calculator we acquire:

\displaystyle  h  \approx 53.6ft

hence,

about <u>5</u><u>3</u><u>.</u><u>6</u><u>f</u><u>t</u> high in the tree ate monkeys

4 0
3 years ago
Pls help 20 points!!
sesenic [268]

Answer:

\huge\boxed{\sf  18 cm\²}

Step-by-step explanation:

The figure consists of 2 rectangles.

<u>Rectangle 1 Area:</u>

Length = 5 cm

Width = 2 cm

Area = Length * Width

A = 5 * 2

A = 10 cm²

<u>Rectangle 2 Area:</u>

Length = 4 cm

Width = 2 cm

Area = 2 * 4

A = 8 cm²

<u>Area of the whole figure:</u>

= Rectangle 1 + Rectangle 2

= 10 + 8

= 18 cm²

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>

3 0
3 years ago
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Complete the table of values for y= x^2-2x-3
Levart [38]

Answer:

x=3,y=0

x=-1,y=0

Step-by-step explanation:

We will have to factorise to get the value of x before solving for y

Let's solve

y=x^2-2x-3

To factorise x

x^2-3x+x-3

x(x-3)+1(x-3)

(x-3)+(x+1)

x-3=0

x=3

x+1=0

x=-1

Let's substitute the value of value to get the value for y

y=x^2-2x-3

When x is 3

y=3^2-2(3)-3

y=9-6-3

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When x is-1

y=(-1)^2-2(-1)-3

y=1+2-3

y=0

Therefore when x is 3,y is 0

When x is -1,y is 0

3 0
4 years ago
Read 2 more answers
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