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4 years ago

Can you please help me find the surface area

Mathematics

1 answer:

arlik [135]4 years ago

6 0

Answer:

392

Step-by-step explanation:

A = BH + 2LS + BL

H = 8

S= 7

L=16

B = 7

7(8) + 2(7)16 + 7(16) = 392

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QUICK MATH EVERY DAY ON THE.....................................................................................................

r-ruslan [8.4K]

Answer:

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Step-by-step explanation:

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3 years ago

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How do you prove a rectangle in geometry?

dedylja [7]

- The opposite sides are parallel and congruent. - The diagonals bisect each other.

- There are 4 right angles. - The diagonals are congruent.

- Show that both pairs of opposite sides are congruent.

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3 years ago

What is the solution set of the compound inequality 3.5x - 10> -3 and 8x -9 <39

Eva8 [605]

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4 years ago

What is the first term in the sequence for which d = -2 and a7 = 3?

AnnZ [28]

Answer:

Final answer is c. 15

Step-by-step explanation:

We need to find about what is the first term in the sequence for which d = -2 and a7 = 3

We will use nth term formula of arithmetic sequence.

$a_n=a+\left(n-1\right)d$

we have been given a7 that means 7th term is 3

so plug n=7, d=-2 and a_n=3 into above formula

$3=a+\left(7-1\right)(-2)$

$3=a+6(-2)$

$3=a-12$

$15=a$

Hence final answer is c. 15

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4 years ago

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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

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4 years ago

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