Answer:
2.652 g/h.
Explanation:
Burn rate (in mg/min) = 44.2 mg/min
Burn rate (in m/h) =?
We'll begin by converting 44.2 mg/min to g/min. This can be obtained as follow:
1 mg/min = 0.001 g/min
Therefore,
44.2 mg/min = 44.2 mg/min × 0.001 g/min / 1 mg/min
44.2 mg/min = 0.0442 g/min
Finally, we shall convert 0.0442 g/min to g/h. This can be obtained as follow:
1 g/min = 60 g/h
Therefore,
0.0442 g/min = 0.0442 g/min × 60 g/h / 1 g/min
0.0442 g/min = 2.652 g/h
Therefore, 44.2 mg/min is equivalent to 2.652 g/h.
Thus, the burn rate (in m/h) is 2.652 g/h.
Answer:
CH₂
Explanation:
From the question given above, the following data were obtained:
Mass of Carbon (C) = 5.41 g
Mass of compound = 6.32 g
Empirical formula =?
Next, we shall determine the mass of Hydrogen (H) in the compound. This can be obtained as follow:
Mass of Carbon (C) = 5.41 g
Mass of compound = 6.32 g
Mass of Hydrogen (H) =?
Mass of H = mass of compound – mass of C
Mass of H = 6.32 – 5.41
Mass of H = 0.91 g
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Mass of C = 5.41 g
Mass of H = 0.91 g
Divide by their molar mass
C = 5.41 / 12 = 0.451
H = 0.91 / 1 = 0.91
Divide by the smallest
C = 0.451 / 0.451 = 1
H = 0.91 / 0.451 = 2
Thus, the empirical formula for the compound is CH₂