varying composition is not a property of a pure substance
 
        
             
        
        
        
Answer:
Washing Clothes & Dissolving Sugar 
Explanation:
Think about each application:
1) Washing clothes: You kind of need water to do this, or not much washing can be done. 
2) Linking brake pedals to the brake pads: You don't need any liquids for this. You need solids. 
3) Deodorizing a room: You would problem choose an aerosol, which is sprayed, thus a gas. 
4) Carving a sculpture: You would use solid tool and a sold sculpture. 
5) Dissolving sugar: You need a liquid to dissolve sugar! 
6) Painting a wall: Perhaps, you COULD say that the paint is a liquid... but I'm not sure if that really counts. I believe this application would still be solids. 
7) A gear for a machine is a solid!
 
        
                    
             
        
        
        
PI3, but make sure it is a subscript of 3, not a large number.
        
             
        
        
        
<u>Answer:</u> The rate law expression is ![\text{Rate}=k[NO]^2[O_2]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5E2%5BO_2%5D%5E1) and value of 'k' is
 and value of 'k' is 
<u>Explanation:</u>
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:

Rate law expression for the reaction:
![\text{Rate}=k[NO]^a[O_2]^b](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5Ea%5BO_2%5D%5Eb)
where,
a = order with respect to nitrogen monoxide
b = order with respect to oxygen
- <u>Expression for rate law for first observation:</u>
 ....(1)
       ....(1)
- <u>Expression for rate law for second observation:</u>
 ....(2)
       ....(2)
- <u>Expression for rate law for third observation:</u>
 ....(3)
       ....(3)
Dividing 1 from 2, we get:

Dividing 1 from 3, we get:

Thus, the rate law becomes:
![\text{Rate}=k[NO]^2[O_2]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5E2%5BO_2%5D%5E1)
Now, calculating the value of 'k' by using any expression.
Putting values in equation 1, we get:
![8.55\times 10^{-3}=k[0.030]^2[0.0055]^1\\\\k=1.727\times 10^3M^{-2}s^{-1}](https://tex.z-dn.net/?f=8.55%5Ctimes%2010%5E%7B-3%7D%3Dk%5B0.030%5D%5E2%5B0.0055%5D%5E1%5C%5C%5C%5Ck%3D1.727%5Ctimes%2010%5E3M%5E%7B-2%7Ds%5E%7B-1%7D)
Hence, the rate law expression is ![\text{Rate}=k[NO]^2[O_2]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5E2%5BO_2%5D%5E1) and value of 'k' is
 and value of 'k' is 