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nata0808 [166]
3 years ago
14

Please help me I need help with this questions I’m very confused fused as to what the answer is please

Chemistry
1 answer:
zepelin [54]3 years ago
3 0
Answer: This was because the experiment showed that a substance could emit radiation even while it was not exposed to light.
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Which is not a property of a pure substance?
mr Goodwill [35]

varying composition is not a property of a pure substance

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3 years ago
For which applications would you choose a liquid over a gas or solid?
DedPeter [7]

Answer:

Washing Clothes & Dissolving Sugar

Explanation:

Think about each application:

1) Washing clothes: You kind of need water to do this, or not much washing can be done.

2) Linking brake pedals to the brake pads: You don't need any liquids for this. You need solids.

3) Deodorizing a room: You would problem choose an aerosol, which is sprayed, thus a gas.

4) Carving a sculpture: You would use solid tool and a sold sculpture.

5) Dissolving sugar: You need a liquid to dissolve sugar!

6) Painting a wall: Perhaps, you COULD say that the paint is a liquid... but I'm not sure if that really counts. I believe this application would still be solids.

7) A gear for a machine is a solid!

5 0
3 years ago
Read 2 more answers
How many moles in 58 grams of CO3 ?
Romashka [77]

Answer:

60.0089

Explanation:

7 0
3 years ago
Whats the formula for phosphorus III iodide
Marta_Voda [28]
PI3, but make sure it is a subscript of 3, not a large number.
4 0
3 years ago
Determine the rate law and the value of k for the following reaction using the data provided.
blsea [12.9K]

<u>Answer:</u> The rate law expression is \text{Rate}=k[NO]^2[O_2]^1 and value of 'k' is 1.727\times 10^3M^{-2}s^{-1}

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2NO(g)+O_2(g)\rightarrow 2NO_2(g)

Rate law expression for the reaction:

\text{Rate}=k[NO]^a[O_2]^b

where,

a = order with respect to nitrogen monoxide

b = order with respect to oxygen

  • <u>Expression for rate law for first observation:</u>

8.55\times 10^{-3}=k(0.030)^a(0.0055)^b       ....(1)

  • <u>Expression for rate law for second observation:</u>

1.71\times 10^{-2}=k(0.030)^a(0.0110)^b       ....(2)

  • <u>Expression for rate law for third observation:</u>

3.42\times 10^{-2}=k(0.060)^a(0.0055)^b      ....(3)

Dividing 1 from 2, we get:

\frac{1.71\times 10^{-2}}{8.55\times 10^{-3}}=\frac{(0.030)^a(0.0110)^b}{(0.030)^a(0.0055)^b}\\\\2=2^b\\b=1

Dividing 1 from 3, we get:

\frac{3.42\times 10^{-2}}{8.55\times 10^{-3}}=\frac{(0.060)^a(0.0055)^b}{(0.030)^a(0.0055)^b}\\\\2^2=2^a\\a=2

Thus, the rate law becomes:

\text{Rate}=k[NO]^2[O_2]^1

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

8.55\times 10^{-3}=k[0.030]^2[0.0055]^1\\\\k=1.727\times 10^3M^{-2}s^{-1}

Hence, the rate law expression is \text{Rate}=k[NO]^2[O_2]^1 and value of 'k' is 1.727\times 10^3M^{-2}s^{-1}

4 0
3 years ago
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