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solong [7]
3 years ago
11

The number at the end of an isotope's name is the number

Chemistry
1 answer:
Korolek [52]3 years ago
7 0

Answer:

Atomic neutron mass electron number

Explanation:

You might be interested in
Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a flas
valentina_108 [34]

Answer:

Kp = 0.022

Explanation:

<em>Full question: ...With 2.3 atm of ammonia gas at 32. °C. He then raises the temperature, and when the mixture has come to equilibrium measures the partial pressure of hydrogen gas to be 0.69 atm. </em>

<em />

The equilibrium of ammonia occurs as follows:

2NH₃(g) ⇄ N₂(g) + 3H₂(g)

Where Kp is defined as:

Kp = \frac{P_{N_2}P_{H_2}^3}{P_{NH_3}^2}

<em>Where P represents partial pressure of each gas.</em>

<em />

As initial pressure of ammonia is 2.3atm, its equilibrium concentration will be:

P(NH₃) = 2.3atm - 2X

<em>Where X represents reaction coordinate</em>

<em />

Thus, pressure of hydrogen and nitrogen is:

P(N₂) = X

P(H₂) = 3X.

As partial pressure of hydrogen is 0.69atm:

3X = 0.69

X = 0.23atm:

P(NH₃) = 2.3atm - 2(0.23atm) = 1.84atm

P(N₂) = 0.23atm

P(H₂) = 0.69atm

Kp = \frac{0.23atm*0.69atm^3}{1.84atm^2}

<h3>Kp = 0.022</h3>
8 0
3 years ago
Which of the following is true about metallic bonding?
Anna [14]

Answer:

I think the answer is option B

8 0
3 years ago
Read 2 more answers
2. What would happen if you added more than 5 mL of H2O2 to the 5 mL of yeast solution?
disa [49]

Answer:

The yeast present contains an enzyme called catalase which catalyses the reaction. More the amount of the catalyst added, faster will be the decomposition of the hydrogen peroxide.

4 0
3 years ago
How many moles of calcium carbonate-CaCO3 = 4.15 g​
marin [14]

Answer:

Number of moles = 0.042 mol

Explanation:

Given data:

Number of moles = ?

Mass of calcium carbonate = ?

Solution:

Formula:

Number of moles = mass/ molar mass

now we will calculate the molar mass of calcium carbonate.

atomic mass of Ca = 40 amu

atomic mass of C = 12 amu

atomic mass of O = 16 amu

CaCO₃ = 40 + 12+ 3×16

CaCO₃ = 40 + 12+48

CaCO₃ = 100 g/mol

Now we will calculate the number of moles.

Number of moles = 4.15 g / 100 g/mol

Number of moles = 0.042 mol

3 0
3 years ago
2NO (g) + O2 (g) →2NO2 (g) At equilibrium [NO] = 2.4 × 10 -3 M, [O2] = 1.4 × 10 -4 M, and [NO2] = 0.95 M.
azamat

Answer:

K=1.12x10^9

Explanation:

Hello there!

Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:

K=\frac{[NO_2]^2}{[NO]^2[O_2]}

Then, we plug in the concentrations at equilibrium to obtain the equilibrium constant as follows:

K=\frac{(0.95)^2}{(0.0024)^2(0.00014)}\\\\K=1.12x10^9

In addition, we can infer this is a reaction that predominantly tends to the product (NO2) as K>>>>1.

Best regards!

4 0
3 years ago
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