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Likurg_2 [28]
3 years ago
7

In the figure, which two lines appear to be parallel?

Chemistry
2 answers:
Ipatiy [6.2K]3 years ago
7 0
I don’t understand. Is there a picture? Where are the options?
BARSIC [14]3 years ago
7 0

Answer:

I don't see a picture....

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Does electricity flow from negative to positive right
kirill [66]
Two types of charges are involved in electricity flow, these are positive charges and negative charges. The negative charges are called electrons and they are the ones that are responsible for electricity flow. The negative terminal of a battery for example has excess of electrons while the positive terminal lacks electrons. Thus, electricity flows by the movement of electrons from the negative terminal to the positive terminal.
4 0
3 years ago
Read 2 more answers
Balance the following equations:
Brilliant_brown [7]

Answer:

1) 0 C2H4O2 + 0 O2 -> 0 CO2 + 0 H2O (balanced)

2) V2O5 + CaS -> CaO + V2S5

<em>just additional info: V2O5 </em><em>is</em><em> </em><em>divanadium</em><em> </em><em>pentaoxide</em>

LHS (Left hand side)

V: 2

O: 5

Ca: 1

S: 1 x 5 [to balance with the right hand side of the equation]

RHS (Right hand side)

V: 2

O: 1 x 5 [to balance with the left hand side of the equation]

Ca: 1

S: 5

When you balance any elements, you have to balance the whole chemical compound.

Thus,

V2O5 + <em><u>5</u></em> CaS -> <em><u>5</u> CaO</em> + V2S5

LHS CHECK:

V: 2

O: 5

Ca: 5

S: 5

RHS CHECK:

V: 2

O: 5

Ca: 5

S: 5

3) S8 + O2 -> SO2

LHS:

S: 8

O: 2

RHS:

S: 1 x 8 [to balance with LHS]

O: 2

When you balance any elements, you have to balance the whole chemical compound.

S8 + O2 -> <em><u>8</u></em><em><u> </u></em>SO2

When we add 8 to the RHS, it gives us 8S, 16 O.

In order to balance that into the RHS, I need to multiply the O2 by 8, which will give 8(O2) = 16 O particles.

Therefore, <em><u>S8</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>8</u></em><em><u> </u></em><em><u>O2</u></em><em><u> </u></em><em><u>-</u></em><em><u>></u></em><em><u> </u></em><em><u>8</u></em><em><u> </u></em><em><u>SO2</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>final</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>(</u></em><em><u>3</u></em><em><u>)</u></em><em><u>.</u></em>

6 0
3 years ago
What best explains why sodium is more likely to react with another element than an element such as neon
goblinko [34]

Answer: Neon is not reactive (full valence shell)

Explanation:

Neon is a noble gas and has a stable structure (8 valence electrons) -therefore, is not very reactive.

3 0
4 years ago
If the concentration of products is increased the equilibrium is shifted from * left to right/ to the left/ right to left /down
Marysya12 [62]

Answer:

to the left

Explanation:

<u>If the concentration of products is increased for a reaction that is in equilibrium, the equilibrium would shift to the left side of the reaction (the reactant's side). </u>

For a reaction that is in equilibrium, the reaction is balanced between the reactants and the products. According to Le Cha telier's  principle, if one of the constraints capable of influencing the rate of reactions is applied to such a reaction that is in equilibrium, the equilibrium would shift so as to neutralize the effects created by the constraint.

<em>Hence, in this case, if the concentration of the products of a reaction in equilibrium is increased, the equilibrium would shift in such a way that more reactants are formed so as to annul the effects created by the increase in the concentration of the products. Since reactants are always on the left side of chemical equations, it thus means that the equilibrium would shift to the left.</em>

5 0
3 years ago
Mg + __C12 = ____MgCl2
Gnom [1K]

Explanation:

vgrtyuhjmnikmnbbvfrt5uikmnbgyftyikmnvcfdrtyuikmbnbvfrtyumnbvfujkgtyjuvf

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