Answer:
The heat of vaporisation of methanol is "3.48 KJ/Mol"
Explanation:
The amount of heat energy required to convert or transform 1 gram of liquid to vapour is called heat of vaporisation
When 8.7 KJ of heat energy is required to vaporize 2.5 mol of liquid methanol.
Hence, for 1 mol of liquid methanol, amount of heat energy required to evaporate the methanol is =
= 3.48 KJ
So, the heat of vaporization
Therefore, the heat of vaporization of methanol is 3.48KJ/Mol
Taking into account the definition of density and Archimedes' principle, the beginner bowling ball will float on the water.
But first it is neccesary to know that density is a quantity referred to the amount of mass in a certain volume of a substance or a solid object.
In other words, the density is the relationship between the weight (mass) of a substance and the volume that the same substance occupies.
The expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
In this case, a beginner's bowling ball has a mass of 4.9 kg and a volume of 5.4 liters. This is:
Replacing in the definition of density:
Solving:
<u><em>density=0.907 </em></u><u><em /></u>
On the other hand, Archimedes' principle says that an object immersed in a liquid experiences an upward vertical force equal to the weight of the volume of the dislodged liquid.
The sinking or floating of an object is determined by its density with respect to that of the liquid in which it is submerged.
Considering water as the liquid where the object is submerged in this case, an object with a higher density than water will sink. In contrast, an object with a lower density than water will float.
In this case, considering that water has a density of 1 , the bowling ball for beginners has a lower density. This indicates that, having a lower density than water, the object will float.
In summary, the beginner bowling ball will float on the water.
Learn more about density: