Question

Please help, WILL MARK BRANLIEST

Answer 1

Answer:

The perimeter of triangle is 36 units

Step-by-step explanation:

Theory:

The distance between two point is given by

L=$\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2} }$

As shown in figure,

Let,

Coordinate of the point A is (0,0)

Coordinate of the point B is (10,0)

Coordinate of the point C is (5,12)

Now, Perimeter of triangle is given by

Perimeter=AB+BC+AC

The length of AB:

AB=$\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2} }$

AB=$\sqrt{(10-0)^{2}+(0-0)^{2} }$

AB=$\sqrt{(10)^{2}}$

AB=10 units

The length of BC:

BC=$\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2} }$

BC=$\sqrt{(5-10)^{2}+(12-0)^{2} }$

BC=$\sqrt{(5)^{2}+(12)^{2}}$

BC=13 units

The length of AC:

AC=$\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2} }$

AC=$\sqrt{(0-5)^{2}+(0-12)^{2} }$

AC=$\sqrt{(5)^{2}+(12)^{2}}$

AC=13 units

Thus, The perimeter of triangle is,

Perimeter=AB+BC+AC

Perimeter=10+13+13

Perimeter=36 units