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beks73 [17]
3 years ago
13

Think about a real rocket launching at NASA. What are the action and reaction forces in the launch? Which forces do these action

-reaction forces act against? (gravity? Normal force?)
Physics
2 answers:
Tcecarenko [31]3 years ago
6 0

Answer:

whats the question???

Explanation:

MrRa [10]3 years ago
5 0

Answer:

the force is the fuel in the rocket that helps it lift off

Explanation:

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Two identical billiard balls traveling at the same speed have a head-on collision and rebound. If the balls had twice the mass,
Vinvika [58]

Answer:

a) No difference

Explanation:

Since the billiard balls are identical , they have the same mass. Also they have the same speed

Since the angular momentum is conserved and the total energy is conserved ( if we assume elastic collision)

1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²

where m= mass , vi= initial velocity , vf= final velocity

since m1=m2=m , vi1=vi2=vi

1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²

m * v i² = 1/2 m (v f1² +v f2² )

vi² = 1/2(v f1² +v f2² )

since the 2 balls are indistinguishable from each other (they have identical initial mass and velocity) there is no reason for a preferential speed for one of the balls and therefore its velocities must be equal . Thus vf1=vf2=vf

therefore

v i² = 1/2(v f1² +v f2² ) = v i1² = 1/2* 2vf² = vf²

and thus

vi= vf

in conclusion, there is no difference in speed after the rebound

4 0
3 years ago
How does geosphere interact with biosphere
Marina86 [1]

<span>With a partner, describe interactions in this scene, tracing the movement of materials or energy through all four of Earth's spheres if possible. Plants (biosphere) draw water (hydrosphere) and nutrients from the soil (geosphere) and release water vapor into the atmosphere.</span>
6 0
3 years ago
A bowling ball is launched off the top of a 240-foot tall building. The height of the bowling ball above the ground t seconds af
natima [27]

Answer:

When the ball hits the ground, its velocity is -128 ft/s.

Explanation:

Hi there!

First, let's find the time it takes the ball to reach the ground (the value of t for which s(t) = 0):

s(t) = -16t² + 32t + 240

0 = -16t² + 32t + 240

Solving the quadratic equation with the quadratic formula:

t = 5.0 s (the other solution of the equation is rejected because it is negative).

Now, we have to find the velocity of the ball at t = 5.0 s.

The velocity of the ball is the change of height over time (the derivative of s(t)):

v = ds/dt = s'(t) = -32t + 32

at t = 5.0 s:

s'(5.0) = -32(5.0) + 32 = -128 ft/s

When the ball hits the ground, its velocity is -128 ft/s.

4 0
3 years ago
Suppose you are visiting your uncle at an ocean boat club and you hear that a storm, with high winds, creating large waves is ap
Airida [17]
I would say wait no come back stay here where u will be protected
4 0
3 years ago
A force is acting on a 3-kg object during 5 seconds. If the object initially has a speed of 1.5m/s and after applying the force
uranmaximum [27]

Answer:

1.5 N

Explanation:

You've left us to guess what the question is. I will Assume it is what's the force?

Givens

m = 3 kg

vi = 1.5 m/s

vf = 4 m/s

t = 5 seconds

Formula

F = m * (vf - vi)/t

Solution

F = 3 * (4 - 1.5) / 5

F = 1.5 N

3 0
3 years ago
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