Two 20 ohm resistors are connected in parallel and two 10 ohm resistors are connected in parallel. If these two combinations are
connected in series the equivalent resistance of the combination is: a) 20 ohm b) 10 ohm c) 15 Ohm d) 30 Ohm
1 answer:
C. 15Ω.
The circuit diagram is shown in the first image attached. To solve this problem we have to use the equivalent resistor conected in parallel Req = (R1*R2)/(R1+R2).
Calculating the equivalent resistor in the 20Ω resistor parallel arrangement:
RAeq = [(20*20)/(20+20)] Ω
RAeq = 400/40 Ω
RAeq = 10Ω
Calculating the equivalent resistor in the 10Ω resistor parallel arrangement:
RBeq = [(10*10)/(10+10)]Ω
RBeq = 100/20 Ω
RBeq = 5Ω
Both equivalent resistors are in series. So, in order to calculate the equivalent resistance of the combination:
Rtotal = RAeq + RBeq
Rtotal = 10Ω + 5Ω
Rtotal = 15Ω
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The answer is "".
Explanation:
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Answer:
(i) 12 seconds
(ii) 216 meters from the initial position
(iii) 132 meters from the initial position
(iv) No
Explanation:
Speed of express train =36 m/s
Speed of local train =11 m/s
The initial distance between the local train and passenger train =100 m.
Due to the application of breaks, the express train slows at the rare of
So, the acceleration of the express train, .
(i) Let t be the time the express train takes to stop.
From the equation of motion,
v=u+at
where, v: final velocity, u: initial velocity, a: constant acceleration, t: time taken to change the speed from u to v.
In this case, v=0, u=36 m/s,
So, 0=36+(-3)t
seconds.
(ii) To compute the distance traveled, s, till the express train stops, using
meters.
(iii) The local train is moving at a speed of 11 m/s
So, in 12 seconds, the distance, d, traveled by the local train
d= 11x12=132 meters [as distance= speed x time]
(iv) Let 0 be the reference position which is the initial position of the express train.
So, at the initial time, the position of the local train is at 100m.
After 12 seconds:
The position of the express train is at 216 m [using part (ii)]
and the position of the local train is at 100+132=232m [using part (iii)].
So, the local train is still ahead of the express train, hence the trains didn't collide.