3 years ago

I need help with these questions

1 answer:

6 0

7. PE=0.5×700n/m×0.9m^2
0.9^2=0.81m
0.5×700×0.81= 283.5J

8. 2000=0.5×(x)×1.5m^2
1.5^2= 0.25
0.25×0.5=0.125
2000=0.125 (x)
2000/0.125=x
x=16000 n/m

9. 4000=0.5 (375 n/m)×(x)^2
0.5×187.5 (x)
4000/187.5=21.3333333333

You might be interested in

A circuit with two or more branches for current to flow

Natalija [7]

If there's any point in a circuit where the current has a choice
of which branch to take, then you have a <em>parallel circuit</em>.

4 0

2 years ago

Need help identifying the rest of the elements!

gregori [183]

I think that number five is lithium

6 0

2 years ago

The potential difference in a simple circuit is 2 v and the resistance is 2 ω . what current flows in the circuit? answer in uni

balandron [24]

Hey

Potential Difference given is : 2V

Resistance is : 2 ohms

By Ohm's Law, one can easily utilize the relation :

$v = ir$

Where, { v , i , r } are the potential difference, current and Resistance Respectively.

Hence,
$i = \frac{v}{r} = \frac{2}{2} = 1a$

Hence, the Current is 1 Ampere

7 0

2 years ago

An elements atomic number is 85 how many protons would an atom of this element have?

garik1379 [7]

85 protons are in astatine have.

5 0

2 years ago

Read 2 more answers

PLEASE ANSWER FAST In which of the following situations is the greatest amount of work accomplished? 1. A boy lifts a 2-newton b

GuDViN [60]

Explanation:

Work done is given by the product of force and displacement.

Case 1,

1. A boy lifts a 2-newton box 0.8 meters.

W = 2 N × 0.8 m = 1.6 J

2. A boy lifts a 5-newton box 0.8 meters.

W = 5 N × 0.8 m = 4 J

3. A boy lifts a 8-newton box 0.2 meters.

W = 8 N × 0.2 m = 1.6 J

4. A boy lifts a 10-newton box 0.2 meters.

W = 10 N × 0.2 m = 2 J

Out of the four options, in option (2) ''A boy lifts a 5-newton box 0.8 meters'', the work done is 4 J. Hence, the greatest work done is 4 J.

3 0

3 years ago