A. The magnitude (in N) of the electric force that one particle exerts on the other is 8.60×10⁻⁸ N
B. The force is repulsive
<h3>A. How to determine the magnitude of the electric force</h3>
From the question given above, the following data were obtained:
- Charge 1 (q₁) = 7.03 nC = 7.03×10¯⁹ C
- Charge 2 (q₂) = 4.02 nC = 4.02×10¯⁹ C
- Electric constant (K) = 9×10⁹ Nm²/C²
- Distance apart (r) = 1.72 m
- Force (F) =?
The magnitude of the electric force can be obtained by using the Coulomb's law equation as shown below:
F = Kq₁q₂ / r²
F = (9×10⁹ × 7.03×10¯⁹ × 4.02×10¯⁹) / (1.72)²
F = 8.60×10⁻⁸ N
<h3>B. How to determine whether the force is attractive or repulsive</h3>
From the question given, we were told that:
- Charge 1 (q₁) = 7.03 nC
- Charge 2 (q₂) = 4.02 nC
Since both charge are positive, then the force attraction between them is repulsive as like charges repels and unlike charges attracts
Learn more about Coulomb's law:
brainly.com/question/506926
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Answer:If you add a proton to the atom, it becomes beryllium (atomic number = 4).
It is an ion with a +1 charge, since the number of protons (4) no longer equals
the number of electrons (3).
So you have a beryllium +1 ion - the best answer choice is C.
Explanation:if this isn’t right I am so sorry
