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3 years ago

Which of the following phrases defines the angle of refraction?

2 answers:

7 0

The angle between refracted ray and normal is called the Angle of Refraction. The angle formed by a refracted ray or wave and a line perpendicular to the refracting surface at the point of refraction

allsm [11]3 years ago

5 0

The angle between refracted ray and normal,dont worry,its right-<

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Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia

earnstyle [38]

Answer:

The acceleration of rocket B is -22.24 m/s²

Explanation:

Two rockets are flying in the same direction and are side by side at the

instant their retrorockets fire

That means they started from the same point at the same time

Rocket A has an initial velocity of 5800 m/s

Rocket B has an initial velocity of 8600 m/s

After a time t both rockets are again side by side, the displacement of

each being zero

That means they are in the same position again → s = 0

The acceleration of rocket A is -15 m/s²

We need to find the acceleration for rocket B

We can find the time from the information of rocket A by using the

rule → s = u t + $\frac{1}{2}$ a t²

where s is the displacement, u is the initial velocity, a is the

acceleration, and t is the time

→ s = 0 , u = 5800 m/s , a = -15 m/s²

Substitute these values in the rule

→ 0 = 5800 t + $\frac{1}{2}$ (-15) t²

→ 0 = 5800 t - 7.5 t²

Add 7.5 t² for both sides

→ 7.5 t² = 5800 t

Divide both sides by 7.5 t

→ t = 773.3 s

The time for the both rocket to have displacement zero is 773.3 s

Now we can find the acceleration of the rocket B by using the same

rule above

→ u = 8600 m/s , t = 773.3 , s = 0

→ 0 = (8600)(773.3) + $\frac{1}{2}$ a (773.3)²

→ 0 = 6650380 + 298996.445 a

Subtract 6650380 from both sides

→ -6650380 = 298996.445 a

Divide both sides by 298996.445

→ a = -22.24 m/s²

The acceleration of rocket B is -22.24 m/s²

6 0

4 years ago

What is the main form of energy present in the initial state? (Initial state is when the rubber band is stretched , just before

Korolek [52]

Answer:

elastic potential

Explanation:

the rubber band has the potential to snap back when released.

7 0

3 years ago

Read 2 more answers

A volume of cool air rapidly descends from the top of a mountain. The air is a poor thermal conductor, but its temperature incre

kolbaska11 [484]

Answer:

Adiabatic

Explanation:

An adiabatic process is a thermodynamic process in which the system does not exchange heat with its surroundings. An adiabatic process may also be isentropic, meaning that the process may be reversible. The term adiabatic refers to elements that prevent heat transfer with the environment. An insulated wall is quite close to an adiabatic boundary. Hence the term of the adiabatic wall appears.

Air is a bad thermal conductor, this means that air is a system that makes it difficult to change the temperature with the systems around it, so we can conclude that the above question deals with the thermodynamic process called adiabatic.

8 0

3 years ago

A forest ranger might be ranked as being high in what type of intelligence?

Drupady [299]

<h2>Answer:</h2>

A forest ranger might be ranked as being high in Naturalistic intelligence.

<h2>Explanation:</h2>

Naturalistic intelligence is the type of intelligence that relates the activities of people that how sensitive an individual is to nature and the world. Zookeepers, biologists, gardeners, and veterinarians are among those people who have a higher capability of having high naturalist intelligence. Similarly a ranger who is fighting in forests must also be kept in the same category and he might be ranked as being high in the field of Naturalistic Intelligence.

7 0

3 years ago

A pipe of radius 0.0100 m carries

Leno4ka [110]

The pipe has a cross-sectional area of

π (0.0100 m)² = 0.000100π m² ≈ 0.000314 m²

Each second, one such cross-section of water travels a distance of

(2.33 m/s) • (1 s) = 2.33 m

so that, per second, the pipe carries

(2.33 m) • (0.000100π m²) = 0.000233π m³ ≈ 0.000732 m³

of water into the tank each second. Put another way, 2.33 m of the pipe holds around 0.000732 m³ of water.

Divide the total volume of the tank by this rate:

(1.00 m³) / (0.000233π m³/s) ≈ 1366.14 s ≈ 1370 s

or about 22.8 min, or about 0.379 hr, etc.

3 0

3 years ago