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Tema [17]
3 years ago
11

when you drop a pebble from height h, it reaches the ground with kinetic energy k if there is no air resistance. from what heigh

t
Physics
1 answer:
marysya [2.9K]3 years ago
6 0

Answer:

From the initial height h

Explanation:

When a material or substance is drop from a height h, it possesses potential energy, immediately it is dropped from that height, the potential energy is gradually converted to kinetic energy, it gets to a point where the potential energy equals the kinetic energy, as the material touches the ground, all potential energy has been converted to kinetic energy already

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Can someone please help for a , what am I meant to do
monitta
I’m not sure what your question is but I hope I can be of help. Series would split voltage and have same current all through, whereas parallel would have the same voltage all throughout but would have different amperes(currents)
8 0
3 years ago
A constant net force of 345 N is applied to slide a heavy stationary
liubo4ka [24]

Answer:

P = 517.5 [kg*m/s]

Explanation:

We must remember that momentum is defined as the product of force by the time of force duration.

P=F*t

where:

P = momentum [kg*m/s]

F = force [N]

t = time [s]

P=345*1.5\\P=517.5[kg*m/s]

4 0
3 years ago
Why did the model spacecraft go so much faster than expected on Wednesday?
Andrew [12]

Answer:

The Wednesday test launch stored more potential energy, and launched the spacecraft at a faster speed because the stronger magnetic field closer to the magnet resulted in a greater increase in potential energy.

Explanation:

6 0
3 years ago
Two identical billiard balls traveling at the same speed have a head-on collision and rebound. If the balls had twice the mass,
Vinvika [58]

Answer:

a) No difference

Explanation:

Since the billiard balls are identical , they have the same mass. Also they have the same speed

Since the angular momentum is conserved and the total energy is conserved ( if we assume elastic collision)

1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²

where m= mass , vi= initial velocity , vf= final velocity

since m1=m2=m , vi1=vi2=vi

1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²

m * v i² = 1/2 m (v f1² +v f2² )

vi² = 1/2(v f1² +v f2² )

since the 2 balls are indistinguishable from each other (they have identical initial mass and velocity) there is no reason for a preferential speed for one of the balls and therefore its velocities must be equal . Thus vf1=vf2=vf

therefore

v i² = 1/2(v f1² +v f2² ) = v i1² = 1/2* 2vf² = vf²

and thus

vi= vf

in conclusion, there is no difference in speed after the rebound

4 0
3 years ago
A 12.0-kg block is pushed across a rough horizontal surface by a force that is angled 30.0◦ below the horizontal. The magnitude
Juli2301 [7.4K]

Answer:

157.36 N

Explanation:

Contact force is the force which is created due to contact and it is applied on the contact point . The force applied by body on the surface is its weight .

If R be the reaction force of the ground

R = mg + F son30

= 12 x 9.8 + 75 sin 30

= 117.6 + 37.5

= 155.10 N .

friction force = f

Net force in forward direction = F cos 30 - f  = ma

75cos 30 - f = 12 x 3.2

f = 65 - 38.4

= 26.6 N  

Total force on the surface =√( f² + R² )

√ (26.6² + 155.1²)

= √707.56 + 24056²

=√ 24763.57

= 157.36 N.

contact force = 157.36 N .

6 0
3 years ago
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