A light wave moves from a medium where particles of matter are closely packed to a medium made of very little matter. How do you
2 answers:
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Answer:
The Gravitational Acceleration of the Big planet is G = 3g
where G is the gravitational acceleration of the Big Planet and g is the gravitational acceleration of the Earth
So, it becomes G = 3 x 9.8
G = 29.4
Explanation:
Let's start by calculating the <u>Density of the Earth</u> of mass m anad Radius r
We know that mass is density times the volume
ρ =
m = ρV
we know the volume is V =
(please ignore the symbol of Pi)
m = ρ
Calculating the <u>Density of Big Planet</u>
→For Big Planet we know that radius is 3-times the radius of Earth, that is 3r
M = ρ
So in conclusion, the mass of Earth and the mass of Big planet are related as M = 27m
Now let's come to the Gravitational Force, we know that gravitational force is directly proportional to the mass of the body and inversely proportional to the radius.
→Suppose for Earth: Mass = m, Radius = r
For Big Planet: Mass = M, Radius = R
:
= g : G
=
G =
→ Putting the value of R = 3r and M = 27m
G =
By cutting the terms, we get
G = 3g
value of g= 9.8
G = 3 x
G = 29.4
1) First of all, let's calculate the potential difference between the initial point (infinite) and the final point (d=0.529x10-10 m) of the electron.
This is given by:
Where E is the electric field generated by the proton, which is
where
is the Coulomb constant and 
is the proton charge.
Replacing the electric field formula inside the integral, we obtain
2) Then, we can calculate the work done by the electric field to move the electron (charge
) through this 
. The work is given by
This is given by:
Where E is the electric field generated by the proton, which is
where
Replacing the electric field formula inside the integral, we obtain
2) Then, we can calculate the work done by the electric field to move the electron (charge
Answer:
, inside the plane
Explanation:
We need to calculate the magnitude and direction of the magnetic field produced by each wire first, using the formula
where
is the vacuum permeability
I is the current
r is the distance from the wire
For the top wire,
I = 4.00 A
r = d/2 = 0.105 m (since we are evaluating the field half-way between the two wires)
so
And using the right-hand rule (thumb in the same direction as the current (to the right), other fingers wrapped around the thumb indicating the direction of the magnetic field lines), we find that the direction of the field lines at point P is inside the plane
For the bottom wire,
I = 5.90 A
r = 0.105 m
so
And using the right-hand rule (thumb in the same direction as the current (to the left), other fingers wrapped around the thumb indicating the direction of the magnetic field lines), we find that the direction of the field lines at point P is also inside the plane
So both field add together at point P, and the magnitude of the resultant field is:
And the direction is inside the plane.