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2 years ago

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The aluminum rod AB (G = 26 GPa) is bonded to the brass rod BD (G = 39 GPa). Knowing that portion CD of the brass rod is hollow

and has an inner diameter of 40 mm, determine the total strain energy of the two rods. Take TA = 900 N·m.

1 answer:

xz_007 [3.2K]2 years ago

8 0

Answer:

Explanation:its hard

And ok

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A parallel plate capacitor has circular plates with diameter D=21.5 cm separated by a distance d=1.75 mm. When a potential diffe

OLga [1]

Answer: $E=2.078\times 10^{-10} J/cm^3$

Explanation:

Given

Diameter(D)=21.5 cm

distance between plate=1.75 mm

and we know capacitance is

$C=\frac{\epsilon _0A}{d}$

and we know charge is

Q=CV

and charge density ( $\sigma [tex])[tex]=\frac{Q}{A}=\frac{\epsilon _0AV}{Ad}=\frac{\epsilon V}{d}$

Electric field(E) $=\frac{\sigma }{\epsilon _0}$

Energy density $=\frac{1}{2}\epsilon _0E^2$

Energy desity $=\frac{4\pi \epsilon _0}{8\pi }\frac{V^2}{d^2}$

Energy desity $=\frac{1}{8\pi \cdot 9\times 10^9}\times \left [ \frac{12\times 10^3}{1.75}\right ]^2$

$E=2.078\times 10^{-10} J/cm^3$

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3 years ago

A state trooper chases a speeder along a straight road; with vehicles move at 160 km/h. the siren on the trooperâs vehicle produ

Bas_tet [7]

Since both the speeder and the state trooper are moving at the same speed and same direction, therefore there would be no or zero Doppler shift.

In order to have a Doppler shift, the distance or separation between the state trooper and the speeder must also be changing with time. Which in this case, the distance remains the same or constant since they are moving alike. This is just like what would occur if they were both standing still or parked.

<span>So this further means that the frequency of sound is the same as the frequency heard by the speeder. Therefore the Doppler "shift" of the frequency on the speeder would be <u>zero. </u></span>

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3 years ago

A(n) 72.6 kg astronaut becomes separated from the shuttle, while on a space walk. She finds herself 48.1 m away from the shuttle

netineya [11]

Answer:

The time taken to get the shuttle is 6.91 minutes.

Explanation:

Given that.

Mass of an astronaut, $m_1=72.6\ kg$

Distance between astronaut and shuttle, d = 48.1 m

Mass of the camera, $m_2=0.704\ kg$

Speed of camera, v = 12 m/s

We need to find the time taken by the astronaut to reach her shuttle. Both shuttle and astronaut are at rest, their initial velocities will be equal to 0. Using the conservation of linear momentum as :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\m_1(0)+m_2(0)=m_1v_1+m_2v_2\\\\m_1v_1+m_2v_2=0\\\\v_1=\dfrac{-m_2v_2}{m_1}\\\\v_1=\dfrac{0.704\times 12}{72.6}\\\\v_1=0.116\ m/s$

The time taken to get the shuttle is given by :

$t=\dfrac{d}{v_1}\\\\t=\dfrac{48.1}{0.116}\\\\t=414.65\ s$

or

t = 6.91 minutes

So, the time taken to get the shuttle is 6.91 minutes.

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2 years ago

Which best describes Earth’s magnetic field lines? The field lines go out of Earth near the South Pole, enter Earth in the North

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Answer:

c Im pretty sure. Tell me if it is correct, and brainliest would be a appreciated if it is correct! :)

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sesenic [268]

A point b cause at a it’s gaining kinetic energy and at b it has the most kinetic energy

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2 years ago

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