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Aleksandr-060686 [28]
2 years ago
13

HELP ASAP PLEASE!!!!!!!!

Mathematics
1 answer:
stira [4]2 years ago
3 0

Answer:

b) in the fourth round, there was one team left in the tournament.

c) no because with only one team left, the tournament ends.

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Suppose sin a = 12/13 and sin b= 5/11. FInd cos(a+b)
m_a_m_a [10]

Answer:

1.28 or 912/715

Step-by-step explanation:

sine= opposite side/hypotenuse

cos=adjacent/ hypotenuse

sine a= 12/13 using the Pythagorean Theorem and solve for the missing side. (which is the adjacent side)

cos a = 5/13

Do the same for sine b

cos b= 9.8/11

add both the cosine value

(5/13)+(9.8/11)=1.28 or 912/715 in fraction form

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2 years ago
PLEASE HELP ASAP!! ILL MARK BRAINLIEST!
allochka39001 [22]
B is the correct answer. A,C, and D will all give you the correct slope. 
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3 years ago
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What is the sum of the first seven terms of the geometric series 2 - 10 +50 -...?
Umnica [9.8K]

Answer:

26042.

Step-by-step explanation:

What's the first term of this geometric series?

2.

What's the common ratio of this geometric series?

Divide one of the terms with the previous term. For example, divide the second term -10 with the first term 2.

\displaystyle r = \frac{-10}{2} = -5.

What's the sum of this series to the seventh term?

The sum of the first n terms of a geometric series is:

\displaystyle a_1 \cdot \frac{1-r^{n}}{1-r},

where

  • a_1 is the first term of the series,
  • r is the common ratio of the series, and
  • n is the number of terms in this series.

\displaystyle 2 \times\frac{1- (-5)^{7}}{1- (-5)}=26,042.

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3 years ago
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Westkost [7]
The answer is b = -2h.
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Latoya made 2 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for both necklaces
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its 2.60 for each pendent

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