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qwelly [4]
3 years ago
11

Suppose sin a = 12/13 and sin b= 5/11. FInd cos(a+b)

Mathematics
1 answer:
m_a_m_a [10]3 years ago
6 0

Answer:

1.28 or 912/715

Step-by-step explanation:

sine= opposite side/hypotenuse

cos=adjacent/ hypotenuse

sine a= 12/13 using the Pythagorean Theorem and solve for the missing side. (which is the adjacent side)

cos a = 5/13

Do the same for sine b

cos b= 9.8/11

add both the cosine value

(5/13)+(9.8/11)=1.28 or 912/715 in fraction form

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Y = 3/2x + 3<br> The slope and y-intercept
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Answer:

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Y-intercept=3

Step-by-step explanation:

7 0
2 years ago
True or False? A circle could be circumscribed about the quadrilateral below.
SVEN [57.7K]

Answer:

<em>The correct answer is:   False</em>

Step-by-step explanation:

<u>If the sum of the opposite angles in a quadrilateral is 180°</u>, then a circle can be circumscribed about the quadrilateral.

Here,  \angle B+\angle D= 110\°+90\° = 180\°

but,  \angle A+\angle C= 70\°+90\°= 160\°

So, a circle can't be circumscribed about the given quadrilateral.

7 0
3 years ago
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Anastasy [175]

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X=10 and

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4 0
3 years ago
What is the solution of log4(2x-6)=2
Flauer [41]

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Step-by-step explanation:

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Now you can solve for the variable "x":

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And finally you must divide both sides of the equation by 2, then:

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3 0
3 years ago
Transform x2 + 6x + 8 = 0 into the form (x − p)2 = q?
liraira [26]
So hmmm x²+6x+8=0

alrite.. let's do some grouping now
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let's take a peek at the middle guy of the trinomial.. 6x.. hmmm let's factor it, 2*3*x, wait a minute!  2 * 3 * x... we already have x² on the left-side, since the middle term is just 2 * the square root of the other two terms, that means that the guy on the right, our missing guy must be "3"

alrite, let's add 3² then, however, bear in mind that, all we're doing is borrowing from our very good friend Mr Zero, 0

so if we add 3², we also have to subtract 3², let's do so

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(x² + 6x +3²) + 8 - 3² = 0

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5 0
3 years ago
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