Answer:
there is no picture... but i will try my best to help you if you post picture in another question
23/10 = 2 and 3/10
I hope this helped
Answer:
Tommy had 56 cents in start and Loren had 7 cents in start.
Step-by-step explanation:
Let,
x be the money Tommy have.
y be the money Loren have.
According to given statement;
Tommy had 8 times more money than Loren.
x = 8y Eqn 1
Parents gave 35 cents to Loren and Tommy spent 14 cents, therefore
x-14=y+35 Eqn 2
Putting x=8y in Eqn 2
![8y-14=y+35\\8y-y=35+14\\7y=49](https://tex.z-dn.net/?f=8y-14%3Dy%2B35%5C%5C8y-y%3D35%2B14%5C%5C7y%3D49)
Dividing both sides by 7
![\frac{7y}{7}=\frac{49}{7}\\y=7](https://tex.z-dn.net/?f=%5Cfrac%7B7y%7D%7B7%7D%3D%5Cfrac%7B49%7D%7B7%7D%5C%5Cy%3D7)
Putting y=7 in Eqn 1
![x=8(7)\\x=56](https://tex.z-dn.net/?f=x%3D8%287%29%5C%5Cx%3D56)
Hence,
Tommy had 56 cents in start and Loren had 7 cents in start.
So. let's say the numbers are "a" and "b"
whatever they're, we know a + b = 56
let's say the larger one is "b", so 3 times the smaller is 3*a or 3a
now, 12 less than that, is 3a - 12
and the larger is that, so b = 3a - 12
so
![\bf \begin{cases} a+b=56\\ \boxed{b}=3a-12\\ ----------\\ a+\boxed{3a-12}=56 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0Aa%2Bb%3D56%5C%5C%0A%5Cboxed%7Bb%7D%3D3a-12%5C%5C%0A----------%5C%5C%0Aa%2B%5Cboxed%7B3a-12%7D%3D56%0A%5Cend%7Bcases%7D)
solve for "a", to see what the smaller one is
what's b? well, b = 56 - a
Gino studied for 5/4 hours in all. To get this, do 3+2 for the numerator and just put 4 as the denominator. (Four just stays the same the denominator is all fours. If you want more details just put it on comments.) Now you have the answer: 5/4 hours.