Answer:
The answer is 18p^3r and 63p^3
Step-by-step explanation:
G.C.F of 18p^3 r and 45p^4q is = 9p^3
18p^3r = 2*3*3*p*p*p*r
45p^4q = 3*3*5*p*p*p*q
Thus the G.C.F is 3*3*p*p*p = 9p^3
G.C.F of 63p^3 and 45p^4q is = 9p^3
63p^3 = 3*3*7*p*p*p
45p^4q = 3*3*5*p*p*p*q
Thus the G.C.F is 3*3*p*p*p = 9p^3
Therefore the answer is 18p^3r and 63p^3....
X^2+4x+4 and there is no remainder
Answer:
21 h^10
Step-by-step explanation:
(7h^3)(3h^7)
Lets multiply
7*3 h^3 h^7
When the bases are the same , we add the exponents (x^a * x^b) = x ^ (a+b)
21 h^(3+7)
21 h^10