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ryzh [129]
2 years ago
5

.........................................................................................................

Mathematics
1 answer:
erastova [34]2 years ago
4 0

Answer:

I have no clue... I'm very sorry...

Step-by-step explanation:

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What is the value of p so the expression 4/5-3n is equivalent to p(4-15n)
Karolina [17]
P=1/5. factor out the p to get 4p-15pn=4/5p-3n and just solve to get p=1/5
6 0
3 years ago
Luca has 15
pav-90 [236]

Answer:10 question 1/2

Step-by-step explanation:

6 0
3 years ago
Write the numerical expression to represent the following phrase: Three piles of eight pennies each, with two left over. Calcula
mr_godi [17]
Your answer woild be 3×8+2 and if solved equals 26
7 0
3 years ago
I need help please! If you do know the answer help me understand
koban [17]

Answer:

1017.4 m³

Step-by-step explanation:

Volume of cone V = (1/3)πr²h

pi = 3.14

r = 9 and r² = 81 m²

h = 12 m

V = (1/3)*3.14*81*12

V = 1017.36 rounded 1017.4 m³, which is the first answer.

5 0
3 years ago
Show that if S1 and S2 are subsets of a vector space V such that S1 c S2 then span(S1) c span(S2). In particular, if S1 c S2 the
klemol [59]

Answer:

See proof below

Step-by-step explanation:

Assume that V is a vector space over the field F (take F=R,C if you prefer).

Let x\in span(S_1). Then, we can write x as a linear combination of elements of s1, that is, there exist v_1,v_2,\cdots,v_k \in S_1 and a_1,a_2,\cdots,a_k\in F such that x=a_1v_1+a_2v_2+\cdots+a_kv_k. Now, S_1\subseteq S_2 then for all y\in S_1 we have that y\in S_2. In particular, taking y=v_j with j=1,2,\cdots,k we have that v_j\in S_2. Then, x is a linear combination of vectors in S2, therefore x\in span(S_2). We conclude that span(S_1)\subseteq span(S_2).

If, additionally  S_2\subseteq S_1 then reversing the roles of S1 and S2 in the previous proof, span(S_2)\subseteq span(S_1). Then span(S_1)\subseteq span(S_2)\subseteq span(S_1), therefore span(S_1)=span(S_2).

5 0
3 years ago
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