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I am Lyosha [343]
2 years ago
7

What is the solution to the equation -√(15+x)=-3?

Mathematics
2 answers:
marin [14]2 years ago
7 0
So, the negative would be divided out to make it 3, then square both sides to get rid of the square root and get 9, then subtract 15 and you get -6.  <span />
kifflom [539]2 years ago
5 0
X=-6

----------------
Plug in  -6 for  x 
<span>√15+(-6) = 3
</span>Simplify
<span>√9 = 3
Solution is x=-6
</span>
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Choose the correct simplification of the expression a6b3/a4b2
Law Incorporation [45]

Answer:

a2b

Step-by-step explanation:

a6b3 / a4b2

When dividing exponents, you subtract them.

a6-4

b3-2

Leaving you with a2b


8 0
3 years ago
A sector of a circle of radius 6cm subtends an angle in of 105 at the centre of the circle.Calculate
Snowcat [4.5K]

Answer:

c

Step-by-step explanation:

the perimeter of the sector

8 0
2 years ago
Read 2 more answers
Solve the equation.<br><br> x−8π=π<br> x=
VladimirAG [237]
Add 8π to both sides

x-8π+8π=π+8π

x=π+8π

x=9π
7 0
3 years ago
Please help me on this ​
garri49 [273]

Answer:

It's not specific enough, I'll come back to you!

6 0
2 years ago
I need help with #47 to #50 ASAP…. Please help me with it
Ksenya-84 [330]

Step-by-step explanation:

a triangular number n is the sum of all natural numbers <= n.

t1 = 1

t2 = 1+2 = 3

t3 = 1+2+3 = 6

t4 = 1+2+3+4 = 10

...

so,

tn = tn-1 + n

47.

1×8 + 1 = 9 is a square number.

3×8 + 1 = 25 is a square number

6×8 + 1 = 49 is a square number

10×8 + 1 = 81 is a square number

48.

1/3 = 0 remainder 1

3/3 = 1 remainder 0

6/3 = 2 remainder 0

10/3 = 3 remainder 1

15/3 = 5 remainder 0

21/3 = 7 remainder 0

28/3 = 9 remainder 1

so, there seems to be a pattern 1 0 0 1 0 0 1 0 0 1 ...

49.

1/4 = 0 remainder 1

4/4 = 1 remainder 0

9/4 = 2 remainder 1

16/4 = 4 remainder 0

25/4 = 6 remainder 1

36/4 = 9 remainder 0

49/4 = 12 remainder 1

so, there seems to be a pattern 1 0 1 0 1 0 1 0 1 0 1 ...

50.

polygonal numbers is the real name for this.

the formula for dimensions = 5 is

(3n² − n)/2

for dimensions = 6 it is

2n² - n

so, dimensions=5 (and therefore dividing also by 5) we get the remainders

1/5 = 0 remainder 1

5/5 = 1 remainder 0

12/5 = 2 remainder 2

22/5 = 4 remainder 2

35/5 = 7 remainder 0

51/5 = 10 remainder 1

70/5 = 14 remainder 0

92/5 = 18 remainder 2

117/5 = 23 remainder 2

145/5 = 29 remainder 0

here the pattern is 1 0 2 2 0 1 0 2 2 0 1 0 2 2 0 ...

dimensions=6 (and therefore dividing also by 6) we get the remainders

1/6 = 0 remainder 1

6/6 = 1 remainder 0

15/6 = 2 remainder 3

28/6 = 4 remainder 4

45/6 = 7 remainder 3

66/6 = 11 remainder 0

91/6 = 15 remainder 1

120/6 = 20 remainder 0

153/6 = 25 remainder 3

190/6 = 31 remainder 4

231/6 = 38 remainder 3

276/6 = 46 remainder 0

325/6 = 54 remainder 1

here the pattern is 1 0 3 4 3 0 1 0 3 4 3 0 1 0 3 4 3 0 ...

8 0
3 years ago
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