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I am Lyosha [343]
2 years ago
7

What is the solution to the equation -√(15+x)=-3?

Mathematics
2 answers:
marin [14]2 years ago
7 0
So, the negative would be divided out to make it 3, then square both sides to get rid of the square root and get 9, then subtract 15 and you get -6.  <span />
kifflom [539]2 years ago
5 0
X=-6

----------------
Plug in  -6 for  x 
<span>√15+(-6) = 3
</span>Simplify
<span>√9 = 3
Solution is x=-6
</span>
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The ratio of black bags to blue bags is 5to 3 if there are a total of 10 black bags ,then how many blue bags are there
LuckyWell [14K]

Answer:

6

Step-by-step explanation:

We can think of the 10 black bags as 2 sets of 5-black bags (10 divided into groups of 5; 10 / 5 ; is 2 groups/sets). So, we would also have two sets of 3 (3 x 2 = 6), or 6 bags.

5 : 3 = 10 : 6

(multiply both numbers by 2)

4 0
2 years ago
Find the length of each missing side and each missing angle in the isosceles triangle below.
Zarrin [17]

Answer:

x = 45

y = 45

z = 11.1

Step-by-step explanation:

Remark

The triangle is a right triangle. That means that it has 1 right angle.

It is also isosceles which means that the two legs that are not the hypotenuse are equal.

Result: z and 11.1 are equal z = 11.1

More remark

If the triangle is isosceles, that means that the angles that are not right angles must also be equal.

90 + x + y = 180

but x = y

90 + 2x = 180                  Subtract 90

2x = 180 - 90                   Divide by 2

2x/2 = 90/2

x = 45

3 0
2 years ago
The cost of a student ticket to the school play is $7. Write an equation that correctly relates the total cost, c, for a particu
Mazyrski [523]
C = $7s
independent variable ie the changing variable is s
dependent variable ie the non changing variable is c
8 0
2 years ago
Read 2 more answers
A box is 50 cm long. Which of these is closest to the length of this box in feet? (1 inch = 2.54 cm)
goblinko [34]

First, convert cm to inches.

50/2.54 is roughly 19.69

There are 12 inches in a foot, so divide the 19.69 by 12.

19.69/12 is roughly 1.64

So the answer is C

3 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
astra-53 [7]

Answer:

3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow  y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}

Step-by-step explanation:

The period of the functions y=a\cos(bx+c) , y=a\sin(bx+c), y=a\sec (bx+c) or y=a\csc(bx+c) can be calculated as

T=\dfrac{2\pi}{b}

The period of the functions y=a\tan(bx+c) or y=a\cot(bx+c) can be calculated as

T=\dfrac{\pi}{b}

A. The period of the function y=-3\tan 3x is

T=\dfrac{\pi}{3}

B. The period of the function y=6\sin 3x is

T=\dfrac{2\pi}{3}

C. The period of the function y=-4\cot \dfrac{x}{4} is

T=\dfrac{\pi}{\frac{1}{4}}=4\pi

D. The period of the function y=2\cos \dfrac{2x}{3} is

T=\dfrac{2\pi}{\frac{2}{3}}=3\pi

E. The period of the function y=-\dfrac{2}{3}\sec \dfrac{x}{5} is

T=\dfrac{2\pi}{\frac{1}{5}}=10\pi

5 0
3 years ago
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