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ruslelena [56]
3 years ago
8

What = 102 answer plz

Mathematics
2 answers:
blsea [12.9K]3 years ago
6 0
100+2 or 50+52 these would both work
Alexxx [7]3 years ago
5 0
50+52. 40+62. 31+71 and all of those questions equal 102
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A factory packs 25 small shirts,30 medium shirtsand 15 large shirts in a box. If 550 boxes are packed with these shirts,how many
stealth61 [152]

Answer: the total number of shirts in all the boxes is 38500

Step-by-step explanation:

A factory packs 25 small shirts,30 medium shirt sand 15 large shirts in a box. This means that the total number of shirts that is packed into a box would be the sum of the small shirt, medium shirt and large shirt. It becomes

25 + 30 + 15 = 70

If 550 boxes are packed with these shirts, it means that the total number of shirts in all the boxes would be

550 × 70 = 38500

6 0
3 years ago
What is the answer?
Readme [11.4K]

Answer:

3,6

Step-by-step explanation:

7 0
3 years ago
A grocery store advertises that 15 cups of granola cost $6.75. Which are equivalent prices
fgiga [73]

which of what are equivilent prices?

6 0
3 years ago
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8.42 Three bags of jelly beans contain 26,28 , and 30 beans. In each bag, the percent of the beans that are yellow is 50%, 25%,
olasank [31]

Answer:

Step-by-step explanation:

Figure out the number of yellow beans in each bag:

Bag A: 0.5*26 = 13 beans

Bag B: 0.25*28 = 7 beans

Bag C: 0.2*30 = 6 beans

The total number of beans in the bowl: 26+28+30 = 84

Total number of yellow beans: 13+7+6 = 26

Percentage of yellow beans: 26/84 *100 = 30.9523

Rounded answer: 31%

6 0
2 years ago
Read 2 more answers
The amount of money spent on textbooks per year for students is approximately normal.
Ostrovityanka [42]

Answer:a

a

   336.04    <  \mu < 443.96

b

  The  margin of error will increase

c

The  margin of error will decreases

d

The 99% confidence interval is  0.4107 <  p  < 0.4293

Step-by-step explanation:

From the question we are  told that

   The sample size  n =  19

    The sample mean is  \= x  = \$\  390

    The  standard deviation is  \sigma =  \$ \  120

 

Given that the confidence level is  95% then the level of significance is mathematically represented as

           \alpha = 100 -  95

          \alpha  =  5 \%

          \alpha  =  0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table

    So  

         Z_{\frac{\alpha }{2} } =  1.96

The  margin of error is mathematically represented as

      E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>    E = 1.96 *  \frac{120}{\sqrt{19} }

=>   E = 53.96

The 95% confidence interval is  

     \= x  -  E  <  \mu < \= x  +  E

=>   390  -   53.96   <  \mu < 390  -   53.96

=>  336.04    <  \mu < 443.96

When the confidence level increases the Z_{\frac{\alpha }{2} } also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

         n  \  \ \alpha  \ \  \frac{1}{E^2 }

So if the sample size increases the margin of error decrease

The  sample proportion is mathematically represented as

       \r p  =  \frac{210}{500}

       \r p  = 0.42

Given that the confidence level is 0.99 the level of significance is  \alpha =  0.01

The critical value of \frac{\alpha }{2} from the normal distribution table is  

      Z_{\frac{\alpha }{2} }  =  2.58

  Generally the margin of error is mathematically represented as

       E =  Z_{\frac{\alpha }{2} }*  \sqrt{ \frac{\r p (1- \r p )}{n} }

=>   E =  0.42 *  \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }

=>     E =  0.0093

The 99% confidence interval  is

     \r p  -  E <  p  < \r p  +  E

     0.42  -  0.0093 <  p  < 0.42  +  0.0093

     0.4107 <  p  < 0.4293

 

4 0
3 years ago
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