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3 years ago

What is the LCM of 25 and 35

Mathematics

1 answer:

Naily [24]3 years ago

4 0

Answer:

175

Step-by-step explanation:

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Does the graph represent a function? <br> Yes Or No

Vesna [10]

Answer:

Yes.

Step-by-step explanation:

First, draw a vertical line. Then check the interception between the graph and a vertical line.

If the line intercepts the graph only one point, then it is a function. Otherwise, it is not. That includes two or more.

The graph shown in the picture is a function (Cubic Function).

3 0

3 years ago

Read 2 more answers

this week you read 57 pages. this is seven more than two times the number of pages read last week. write an equation and solve.

spayn [35]

57 = 7 + 2x
50 = 2x
x = 25

x being the number of pages read last week

Hope this helps a little!!

7 0

3 years ago

Help please ASAP please I’ll mark you as brainlister

storchak [24]

Answer:

a = 4

Step-by-step explanation:

$\sin(theta) = \frac{opposite}{hypotenuse}$

$\cos(theta) = \frac{adjacent}{hypotenuse}$

$\tan(theta) = \frac{opposite}{adjacent}$

hypotenuse = a

opposite = 2√3

adjacent = b

theta = 60°

the best formula to use is the first formula cause we have all the values to substitute in it in order to find the value of a

$\sin(60) = \frac{2 \sqrt{3} }{a}$

$\frac{2 \sqrt{3} }{ \sin(60) } = a$

$4 = a$

$a = 4$

4 0

3 years ago

Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =

irga5000 [103]

Answer: The required solution is $y=50e^{0.1386t}.$

Step-by-step explanation:

We are given to solve the following differential equation :

$\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

$\dfrac{dy}{y}=kdt.$

Integrating both sides, we get

$\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]$

Also, the conditions are

$y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50$

and

$y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.$

Thus, the required solution is $y=50e^{0.1386t}.$

8 0

3 years ago

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a ship sails 20km due north. It changes direction and then sails 15 due east. How far is it from its starting point?

Feliz [49]

It is 35km from its starting point

7 0

3 years ago