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Brilliant_brown [7]
3 years ago
5

Solve the inequality: 6x - 36 > -2x - 14

Mathematics
2 answers:
iren2701 [21]3 years ago
6 0

Answer:

x > 11/4

Step-by-step explanation:

ycow [4]3 years ago
6 0

To solve the inequality, you need to isolate/get the variable "x" by itself in the inequality:

6x - 36 > -2x - 14     Add 2x on both sides to get "x" on one side of the inequality

6x + 2x - 36 > -2x + 2x - 14

8x - 36 > -14         Add 36 on both sides

8x - 36 + 36 > -14 + 36

8x > 22         Divide 8 on both sides to get "x" by itself

\frac{8x}{8} >\frac{22}{8}       Simplify \frac{22}{8}

x > \frac{11}{4}            

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7 0
3 years ago
Madelyn is working two summer jobs, making $20 per hour lifeguarding and making $12 per hour clearing tables. In a given week, s
Kamila [148]

Answer:

The possible values of the number of hours clearing tables are 2 , 3 , 4 , 5 hours

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- Madelyn is making $20 per hour life guarding

- She is making $12 per hour clearing tables

- She can work no more than 13 total hours

∴ The greatest time she can work is 13 hours (≤)

- She must earn no less than $180

∴ The least money she wants to earn is $180 (≥)

- If Madelyn worked 8 hours life guarding and assume that she

 worked x hours clearing tables

∵ She can work no more than 13 hours

∴ 8 + x ≤ 13

- Subtract 8 from both sides

∴ x ≤ 5 ⇒ (1)

∵ She must earn no less than $180

∴ 8 × 20 + x × 12 ≥ 180

∴ 160 + 12x ≥ 180

- Subtract 60 from both sides

∴ 12x ≥ 20 ⇒ (2)

- From equation (1) ⇒ x = 1 , 2 , 3 , 4 , 5

- Substitute x in equation (2) by these values to find the right values

 of x

# If x = 1

∴ 12(1) ≥ 20

- But 12 is less than 20

∴ x can not be 1

# x = 2

∴ 12(2) ≥ 20

∴ 24 ≥ 20

- 24 is greater than 20 then x can be 2

∵ 3 , 4 , 5 greater than 2

∴ All of them give answers greater than 20

∴ x can be 3 , 4, 5

∵ x represents the number of hours for clearing tables

∴ The possible values of the number of hours clearing tables are

   2 , 3 , 4 , 5 hours

5 0
3 years ago
If Kevin wants a 90 average in math after 5 tests and his first 4 tests are 76, 92, 89 and 97 what does he need on the fifth tes
Keith_Richards [23]
You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
(87 + 88 + 92 + X) / 4 = 90
Now you need to solve for X, the unknown:
87
+
88
+
92
+
X
4
(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
87 + 88 + 92 + X = 360
This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.
4 0
3 years ago
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I believe it’s 9/30
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What is the formula to find sin
jolli1 [7]
The formula is Opposite/Hypotenuse
8 0
3 years ago
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