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Nataly [62]
3 years ago
15

a laptop's screen is 8 inches long. if the diagonal measures 10 inches, what is the width of the laptop

Mathematics
1 answer:
Ray Of Light [21]3 years ago
5 0
The width of the laptop is 6 inches long.
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In old-growth forests of douglas fir, the spotted owl dines mainly on flying squirrels. If we left When the initial population i
Delicious77 [7]

Answer: There are 667 owls for every 1000 squirrels.

Step-by-step explanation:

Since we have given that

Number of owls = 30

Number of squirrels = 45

If the number of owls and squirrels will continue to increase.

If there are 1000 squirrels, then the number of owls would be

\dfrac{30}{45}=\dfrac{x}{1000}\\\\x=\dfrac{30\times 1000}{45}\\\\x=666.67\\\\x\approx 667

Hence, there are 667 owls for every 1000 squirrels.

5 0
3 years ago
The diameter of a circle has endpoints whosever coordinates are R(-2,2) and S(4,2). find the center of the circle
ZanzabumX [31]
You can use midpoint formula
M=x1+x2/2 , y1+y2/2
M=-2+4/2 , 2+2/2
M= 1,2
8 0
3 years ago
The line plot shows the number of miles Scarlet walked each day last week. What is the total number of miles Scarlet walked last
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5 0
3 years ago
Read 2 more answers
Please help, I need this .
ohaa [14]
14.4, if my calculator was correct
4 0
3 years ago
Suppose that replacement times for washing machines are normally distributed with a mean of 9.3 years and a standard deviation o
Harlamova29_29 [7]

Answer:

The probability is 0.0643

Step-by-step explanation:

* Lets revise some definition to solve the problem

- The standard deviation of the distribution of sample means is called σM

- σM = σ/√n , where σ is the standard deviation and n is the sample size

- z-score = (M - μ)/σM, where M is the mean of the sample , μ is the mean

 of the population  

* Lets solve the problem

- The mean of the washing machine is 9.3 years

∴ μ = 9.3

- The standard deviation is 1.1 years

∴ σ = 1.1

- There are 70 washing machines randomly selected

∴ n = 70

- The mean replacement time less than 9.1 years

∴ M = 9.1

- Lets calculate z-score

∵ σM = σ/√n

∴ σM = 1.1/√70 = 0.1315

∵ z-score = (M - μ)/σM

∴ z-score = (9.1 - 9.3)/0.1315 = - 1.5209

- Use the normal distribution table of z to find P(z < -1.5209)

∴ P(z < -1.5209) = 0.06426

∵ P(M < 9.1) = P(z < -1.5209)

∴ P(M < 9.1) = 0.0643

* The probability is 0.0643

5 0
3 years ago
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