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alekssr [168]
4 years ago
9

1-Milk and dairy products are excellent sources for:

Biology
1 answer:
Zarrin [17]4 years ago
6 0
I know the first is a.
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You advise your pregnant friend to give her cat away becauseA. She could contract plague.B. She could give the cat tularemia.C.
Aneli [31]

Answer:

c. she could get toxoplasmosis

Explanation:

she would be exposed to cat litter; cat litter usually carries those parasites that cause toxoplasmosis.

3 0
3 years ago
Long, saturated fatty acid tails ____________ lipid mobility and ____________ membrane fluidity.
Eduardwww [97]

Long saturated fatty acid tails reduces lipid mobility while decreases membrane fluidity. It is because this is the saturated fatty acids’ function and if it has reduced the lipid mobility, this will also decrease the fluidity of the membrane of the individual.

3 0
3 years ago
Summarize the steps that occur in the process of chromosomal DNA replication. Please place the following steps in the proper ord
grandymaker [24]

Answer:

The proper order is:

A. DnaA proteins bind to the origin of replication, resulting in the separation of the AT-rich region.

B. DNA helicase breaks the hydrogen bonds between the DNA strands, topoisomerases alleviate positive supercoiling, and single-strand binding proteins hold the parental strands apart.

C. Topoisomerases unravel the intertwined chromosomes, if necessary.

D. Primase synthesizes one RNA primer in the leading strand and many RNA primers in the lagging strand, and DNA polymerase III synthesizes the daughter strands of DNA.

E. DNA polymerase I removes the RNA primers and fills in that region with DNA, and DNA ligase covalently links Okazaki fragments together.

F. Replication continues until the two replication forks meet on the other side of the circular bacterial chromosome.

Explanation:

The process of DNA replication in prokaryotes starts at a point called ORIGIN OF REPLICATION. This site is where certain proteins recognize and bind to in order to kickstart the replication process. The following are orderly processes of DNA replication.

- DnaA proteins bind to the origin of replication, resulting in the separation of the AT-rich region.

- DNA helicase breaks the hydrogen bonds between the DNA strands to form two replication forks, topoisomerases prevent supercoiling of these separated DNA, and single-strand binding proteins hold the parental single strands apart, hence, making sure that they do not rewind again.

- In case DNA rewinds, topoisomerases unravel or disentangles the intertwined chromosomes, if necessary.

- DNA Primase synthesizes one RNA primer in the leading strand and many RNA primers in the lagging strand,which allows DNA polymerase III synthesize the daughter strands of DNA. Note that the synthesis of nucleotides on threading strand is continuous while nucleotides are synthesized in small fragments called OKAZAKI FRAGMENTS, on the lagging strand.

- DNA polymerase I removes the RNA primers and replaces with synthesized DNA in that region, and DNA ligase covalently links the Okazaki fragments (small fragments of DNA) together.

- Replication continues until the two replication forks meet on the other side of the circular bacterial chromosome.

5 0
3 years ago
In the following example, what is the independent variable? Hypothesis: Mice on a restricted low-caloric diet will live longer t
tatiyna

Answer:

A. amount of food available

Explanation:

An experiment consists of two types of variables, independent and dependent. Value of independent variable is decided by the person doing the experiment and is independent of experimental conditions. Value of dependent variable is dependent on the independent variable. It can not be altered by the person doing experiment.

Here, it is given that mice receive variable amount of food each day and their lifespan is recorded. Since the amount of food is decided already it is the independent variable. The lifespan is expected to depend on the amount of food hence it is the dependent variable.

7 0
3 years ago
Compare each patient's cdna sequence to the wild-type cdna sequence. Each patient has one nucleotide-pair substitution mutation.
Lera25 [3.4K]

The mutation is a change in the nucleotidic sequence. In the exposed example, Patient 1: nucleotide 143, T<u>T</u>C⇒T<u>G</u>C. Patient 2: nucleotide 143, T<u>T</u>C⇒T<u>C</u>C. Patient 3: nucleotide 147, TT<u>C</u> ⇒ TT<u>G</u>.

<h3>What is a mutation?</h3>

A mutation is a change or alteration in DNI sequences that introduce new variants.

Many of these are eliminated, but some of them might succeed and be incorporated into each individual.

These mutations are the ones that have been selected by natural selection.

<h3>Solving the problem</h3>

We know that each sequence initiates with nucleotide number 103 and ends in nucleotide 162.

So first, we will number the nucleotides, from 103 to 162. Each nucleotide has a number in increasing order.

Now, we will identify the mutations in each of the strands by comparing them with the wild-type sequence. The mutation occurs in one of the nucleotides, so we must look for the change in the bases.

Finally, we will identify the nucleotide location of each mutation.

                   nucleotide                 wild-type                mutated

<u>                       location                 nucleotide              nucleotide      </u><u>           </u>

Patient 1            143                         TTC                         TGC

Patient 2           143                         TTC                         TCC

<u>Patient 3           147                          TTC                        TTG                         </u>

<u />

In the attached files you will find an image for a better understanding.

You will learn more about mutations at

brainly.com/question/4347425

brainly.com/question/17914937

 

3 0
3 years ago
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