A <u>Food web</u> is multiple overlapping food chains.
Answer:
The diameter of the moon's image is 0.31 cm.
Explanation:
Given that,
Focal length = 34.3 cm
Diameter of the moon ![d=3.48\times10^{6}\ m](https://tex.z-dn.net/?f=d%3D3.48%5Ctimes10%5E%7B6%7D%5C%20m)
Mean distance from the earth ![d=3.85\times10^{8}\ m](https://tex.z-dn.net/?f=d%3D3.85%5Ctimes10%5E%7B8%7D%5C%20m)
At that distance the object is assumes to be at infinity. hence the image will be formed at a distance equal to focal length
So, the image distance is 34.3 cm.
We need to calculate the diameter of the moon's image
Using formula of magnification
![m= \dfrac{image\ distance}{object\ distance}=\dfrac{height\ of\ image}{height\ of\ object}](https://tex.z-dn.net/?f=m%3D%20%5Cdfrac%7Bimage%5C%20distance%7D%7Bobject%5C%20distance%7D%3D%5Cdfrac%7Bheight%5C%20of%5C%20image%7D%7Bheight%5C%20of%5C%20object%7D)
![\dfrac{0.343}{3.85\times10^{8}}=\dfrac{h'}{3.48\times10^{6}}](https://tex.z-dn.net/?f=%5Cdfrac%7B0.343%7D%7B3.85%5Ctimes10%5E%7B8%7D%7D%3D%5Cdfrac%7Bh%27%7D%7B3.48%5Ctimes10%5E%7B6%7D%7D)
![h'=\dfrac{0.343\times3.48\times10^{6}}{3.85\times10^{8}}](https://tex.z-dn.net/?f=h%27%3D%5Cdfrac%7B0.343%5Ctimes3.48%5Ctimes10%5E%7B6%7D%7D%7B3.85%5Ctimes10%5E%7B8%7D%7D)
![h'=0.0031\ m= 0.31\ cm](https://tex.z-dn.net/?f=h%27%3D0.0031%5C%20m%3D%200.31%5C%20cm)
Hence, The diameter of the moon's image is 0.31 cm.
They both use messenger particles to carry the force. Gluons for the strong force and W and Z for the weak. And both sets of particles solely with the sub atomic particles of the nuclei: quarks and neutrinos. That is, their range is limited to the nuclei of the atoms and the ions.
Answer:
D
Explanation:
Does not assosicate with Light