From the laws of motions:
x = 0.5 at^2 where
x is the displacement
a is the force of gravity (constant = 9.8 m/sec^2)
t is the time taken
Since "a" is constant, therefore:
the displacement is directly proportional to the square of the time.
This means that, increasing the displacement by a factor of 4 would increase the time by a factor of (4)^2 = 16.
Answer:
V = 9.33 V
Explanation:
By definition, the capacitance of a capacitor, is the proportion between the charge on one of charged surfaces and the potential difference between these surfaces, as follows:
![C = \frac{Q}{V}](https://tex.z-dn.net/?f=C%20%3D%20%5Cfrac%7BQ%7D%7BV%7D)
for a parallel-plate type capacitor, it can be showed, applying Gauss'Law to the a gaussian surface with the shape of a pillbox parallel to the surface of one of the plates, half outside the surface, half inside it, that the capacitance can be expressed as follows:
![C =\frac{\epsilon*A}{d}](https://tex.z-dn.net/?f=C%20%3D%5Cfrac%7B%5Cepsilon%2AA%7D%7Bd%7D)
As we can see, if a slab of paraffin, with dielectric constant of 2.25, is inserted, the capacitance will be increased in the same factor:
![Cf = 2.25 * Co](https://tex.z-dn.net/?f=Cf%20%3D%202.25%20%2A%20Co)
Now, if the capacitor, once charged, is disconnected from the battery, the charge Q will remain constant.
So, if the capacitance will be increased 2.25 times, the only way to do this is that the voltage between plates be reduced in the same factor:
![Cf = 2.25 * Co = 2.25* \frac{Q}{Vo} = \frac{Q}{Vf} \\ Vf= \frac{Vo}{2.25} =\frac{21.0V}{2.25} = 9.33 V](https://tex.z-dn.net/?f=Cf%20%3D%202.25%20%2A%20Co%20%3D%202.25%2A%20%5Cfrac%7BQ%7D%7BVo%7D%20%3D%20%5Cfrac%7BQ%7D%7BVf%7D%20%5C%5C%20Vf%3D%20%5Cfrac%7BVo%7D%7B2.25%7D%20%3D%5Cfrac%7B21.0V%7D%7B2.25%7D%20%3D%209.33%20V)
Need a graph or a picture
There will be no way that to happen aton is a positive charge
Answer:
Less than
Explanation:
Speed of sound increases with density of the medium. Since wood is less dense than water, the speed of sound is lower in wood.