Answer:
Speed = 0.00392 m/s
Explanation:
Solution:
Frequency of the radio = 85 MHz
If we have the frequency, we can calculate the wavelength of the radio wave.
As we know,
Frequency = speed of light/wavelength
wavelength = c/f
c = speed of light = 3 x 
m/s
So,
Wavelength = 3 x m/s / 85 x 
Hz
Wavelength = 3.5294 m
Man gets disturbed reception at t = 15 min
t = 15 x 60 = 900 s
t = 900 s
Speed = distance/time
Here, distance is wavelength. So,
Speed = 3.5294 m / 900 s
Speed = 0.00392 m/s
Hence, the man's car is going with speed of 0.00392 m/s
Answer:
The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q.
Explanation:
Electric field strength is a vector quantity; it has both magnitude and direction. The magnitude of the electric field strength is defined in terms of how it is measured. Let's suppose that an electric charge can be denoted by the symbol Q. This electric charge creates an electric field; since Q is the source of the electric field, we will refer to it as the source charge. The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q. When placed within the electric field, the test charge will experience an electric force - either attractive or repulsive. As is usually the case, this force will be denoted by the symbol F. The magnitude of the electric field is simply defined as the force per charge on the test charge.
Hello!
When the Northern Hemisphere is tilted toward the sun, latitudes between the equator and 90°N (the North Pole) are experiencing summer.
Answer:
because there is many places for it to bounce of of creating another soundwave
Answer:
Explanation:
The question relates to motion on a circular path .
Let the radius of the circular path be R .
The centripetal force for circular motion is provided by frictional force
frictional force is equal to μmg , where μ is coefficient of friction and mg is weight
Equating cenrtipetal force and frictionl force in the case of car A
mv² / R = μmg
R = v² /μg
= 26.8 x 26.8 / .335 x 9.8
= 218.77 m
In case of moton of car B
mv² / R = μmg
v² = μRg
= .683 x 218.77x 9.8
= 1464.35
v = 38.26 m /s .
