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ira [324]
3 years ago
13

Which expressions are completely factored? Select each correct answer. 32y10−24=8(4y10−3) 18y3−6y=3y(6y2−2) 16y5+12y3=4y3(4y2+3)

20y7+10y2=5y(4y6+2y) PreviousNext
Mathematics
1 answer:
laila [671]3 years ago
3 0

Answer:

Option A and Option C

Step-by-step explanation:

Option A: 32y^{10}-24 = 8(4y^{10}-3) This is completely factored as 8 is the Highest Common Monomial factor

Option B: 18y^{3}-6y = 3y(6y^{2}-2) This is not completely factored as 2 is still a common factor of 6y2 and -2.

Option C: 16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) This is completely factored as 4y2 is the Highest Common Monomial factor

Option D: 20y^{7}+10y^{2} = 5y(4y^{6}+2y) This is not completely factored as 2y is still a common factor of 4y6 and 2y.

So the options that are completely factored are Option A and Option C

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