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ira [324]
3 years ago
13

Which expressions are completely factored? Select each correct answer. 32y10−24=8(4y10−3) 18y3−6y=3y(6y2−2) 16y5+12y3=4y3(4y2+3)

20y7+10y2=5y(4y6+2y) PreviousNext
Mathematics
1 answer:
laila [671]3 years ago
3 0

Answer:

Option A and Option C

Step-by-step explanation:

Option A: 32y^{10}-24 = 8(4y^{10}-3) This is completely factored as 8 is the Highest Common Monomial factor

Option B: 18y^{3}-6y = 3y(6y^{2}-2) This is not completely factored as 2 is still a common factor of 6y2 and -2.

Option C: 16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) This is completely factored as 4y2 is the Highest Common Monomial factor

Option D: 20y^{7}+10y^{2} = 5y(4y^{6}+2y) This is not completely factored as 2y is still a common factor of 4y6 and 2y.

So the options that are completely factored are Option A and Option C

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(x, y ) = (- 6, 3 )

Since both equations express y in terms of x, we can equate them

2x + 15 = - \frac{1}{3} x + 1

( add \frac{1}{3} x to both sides )

\frac{7}{3} x + 15 = 1 ( subtract 15 from both sides )

\frac{7}{3} x = - 14

( multiply both sides by 3 and divide by 7 )

x = ( 3 × - 14 )/7 = - 6

substitute x = - 6 into either of the 2 equations for y- coordinate )

y = ( 2 × - 6 ) + 15 = 3

solution : (x, y ) = ( - 6, 3 )


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The seventh grade class supplied bags of snacks and beverages for the school dance They supplied19 more beverages than bags of s
Delvig [45]

Answer:

The number of number of bags of snacks = m  = 176

The number of beverages supplied = m + 19  = 176 +9 = 185

Step-by-step explanation:

Let us assume the number of bags of snacks = m

So, the number of beverages supplied = m + 19

Total number of items supplied  =  371

⇒ Number of (snacks + beverages) supplied=  371

⇒   m + (m +19)  = 371

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⇒  m  = 176

Hence the number of number of bags of snacks = m  = 176

So, the number of beverages supplied = m + 19  = 176 +9 = 185

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