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andrey2020 [161]
3 years ago
5

Help urgent please !!!!!

Mathematics
1 answer:
Elza [17]3 years ago
4 0

The answer is the third bubble.

Hope this helps!

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A vegetable garden with an area of 200 square feet is to be fertilized. If the length of the garden is 1 foot less than three ti
charle [14.2K]
Ok so I like to go in steps with these questions- first draw a picture and identify your variables.

W=width
L= 3w-1

Now we know that length times width gets us area so we plug in our variables into the area equation.

200 = w(3w-1)

When you foil that equation you end up with a quadratic : 3w^2-w-200 = 0

Either factor that or use the quadratic formula to get
w= 8.33 and w= -8

Since you can't have a negative dimension you need to use 8.33 and plug it back into your length equation.

Final answer:

w= 8.33ft
l= 23.99ft

*Now I simplified the decimals a little bit so you end up with 199.8ft^2 for the area so just add a few decimals on here and there*
5 0
3 years ago
Read 2 more answers
Ram noticed three students used 1 2/10 dm of tape.what was the total used for three students???
OLga [1]

Answer:

18/5

Step-by-step explanation:

<em>From my understanding, this is 1 whole 2 upon 10</em>

<u>Step 1: Convert mixed fraction into fraction</u>

<em>Multiply whole number by denominator: 1 x 10 = 10</em>

<em>Add numerator: 10 + 2 = 12</em>

<em>Write the result as the numerator and use the same denominator.</em>

12/10

<u>Step 2: Find the total tape used</u>

<em>From my understanding, each student used 12/10 of the tap</em>

<em>So 3 students used: 12/10 x 3 =</em> 18/5

Therefore, the total tape used for three students was 18/5.

!!

7 0
3 years ago
The vertices of triangle RST are R (-7, 5), S(17, 5), T(5, 0). What is the perimeter of triangle RST?
MaRussiya [10]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}

~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill

3 0
1 year ago
On a coordinate plane, points (1, 3), (5, 9), and (7, 12) are plotted. Which of the following statements are true about this gra
Natasha_Volkova [10]

Answer:

its 2,4,6 - b,d,f

Step-by-step explanation:

The three points form a straight line.

The graph does not pass through the origin.

The graph does not a show a proportional relationship.

4 0
3 years ago
Read 2 more answers
Convert the improper fraction to a mixed number​
alex41 [277]
1) 10 3/10
3) 2 1/2
4) 10 2/3
6) 6 1/2
7) 4 3/4
9) 1 8/9
10) 1 5/6
4 0
3 years ago
Read 2 more answers
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