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SpyIntel [72]
3 years ago
14

Hi please help thank you i’ll give brainliest

Mathematics
2 answers:
alex41 [277]3 years ago
6 0

Answer:

The first one and the last one.

Step-by-step explanation:

We cannot pass matter onto non living things and non living things cannot pass matter onto living things.

Alexeev081 [22]3 years ago
6 0
ANSWER: (B,C)
,Hope this helps Thank you
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Bruce is 4 times as old as Indy. 6 years ago, Bruce was 6 times as old as Indy. how old is bruce now?
goblinko [34]
4i = b
6(i-6) = b-6

6(i-6) = 4i - 6
6i - 36 = 4i - 6
2i - 36 = -6
2i = 30
i = 15 years old
b = 60 years old

Check:
15 * 4 = 60
9 * 6 = 54 :)
5 0
3 years ago
OK. these questions are worth ALL my points (55) !
Ratling [72]

Answer:

1. -7

2. 212

3. -49

4.-1,991

5. 78

6. -16

7. 2

8. 100

9. 16

10. 16

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13. |12| = 12

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15. |8|

16.| 10|

17.15

18. 1,400

Step-by-step explanation:

6 0
2 years ago
On Saturday Keisha ran 2.758 kilometers. On Sunday she ran 1.78 kilometers. How Much farther did she run on Saturday than on Sun
Sonja [21]
0.978 is the answer plz tell me if it helped xD
5 0
3 years ago
Read 2 more answers
Simplify the following radical expressions. 100 points<br> √8/√6<br> √2/10<br> √532<br><br> √3k√8
kenny6666 [7]

Answer:

√8/√6=1.632993

√2/10=0.141421

√3k√8=4.898979k

Step-by-step explanation:

or did u want it in a different form

7 0
3 years ago
Y= 3x-1<br> 2x+6=y substitution method
vfiekz [6]

Answer: (7, 20)

Concept:

There are three general ways to solve systems of equations:

  1. Elimination
  2. Substitution
  3. Graphing

Since the question has specific requirements, we are going to use <u>substitution </u>to solve the equations.

Solve:

<u>Given equations</u>

y = 3x - 1

2x + 6 = y

<u>Substitute the y value since both equations has isolated [y]</u>

2x + 6 = 3x - 1

<u>Add 1 on both sides</u>

2x + 6 + 1 = 3x - 1 + 1

2x + 7 = 3x

<u>Subtract 2x on both sides</u>

2x + 7 - 2x = 3x - 2x

\boxed{x=7}

<u>Find the value of y</u>

y = 3x - 1

y = 3(7) - 1

y = 21 - 1

\boxed{y=20}

Hope this helps!! :)

Please let me know if you have any questions

3 0
2 years ago
Read 2 more answers
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