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3 years ago

Hi please help thank you i’ll give brainliest

Mathematics

2 answers:

alex41 [277]3 years ago

6 0

Answer:

The first one and the last one.

Step-by-step explanation:

We cannot pass matter onto non living things and non living things cannot pass matter onto living things.

Alexeev081 [22]3 years ago

6 0

ANSWER: (B,C)
,Hope this helps Thank you

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Is y=6/x-2 linear or nonlinear

zhannawk [14.2K]

Answer:

Non linear. It is a curve not a line.

8 0

3 years ago

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Will give brainliest !please help 4b+7b+5

Alecsey [184]

Answer:

Terms = 4b , 7b , 5

coefficient = 4 , 7

constant = 5

7 0

3 years ago

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The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe

juin [17]

The height of container is 8 feet

Solution:

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

The volume of container is given as:

$v = length \times width \times height$

Given that volume of the container is 216 cubic feet

$216 = l \times w \times h$

Substitute eqn 1 and eqn 2 in above formula

$216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0$

Solve by factoring

$(h-8)(h^2+4h+27) = 0$

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

$h - 8 = 0\\\\h = 8$

Also,

$h^2+4h+27 = 0$

Solve by quadratic equation formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}$

$h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}$

Therefore, on solving we get,

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

Thus solutions of "h" are:

h = 8

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

8 0

3 years ago

Mrs. Stevens is wanting to buy new border for her math bulletin board in the hallway l. The length of the board is 6.9 meters. T

kiruha [24]

Answer:

The quantity of board which Mr. Stevens need to buy is 22.4 meters

Step-by-step explanation:

Given as :

The length of board = 6.9 meters

The width of board = 4.3 meters

Let The measure of new board = x meter

Now,

The measure of new board = The perimeter of board

∵ The board is of rectangle figure

As, The perimeter of rectangular board = 2 × Length + 2 × width

So, The measure of new board = 2 × Length + 2 × width

or, x = 2 × 6.9 + 2 × 4.3

or, x = 13.8 + 8.6

or, x = 22.4 meters

So, The measure of new board = x = 22.4 meters

Hence The quantity of board which Mr. Stevens need to buy is 22.4 meters Answer

3 0

3 years ago

What is the value of cos x°?

PolarNik [594]

Answer:

We know,

$\cos(x) = \frac{b}{h} = \frac{15}{17}$

$\cos(x) = 0.88$

.....Hope this helps:)

3 0

2 years ago