Answer:
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Intelligent Muslim,
From Uzbekistan.
HELP PLEASE I NEED TO GET IT DONE BECAUSE ILL BE WITH MY FAMILY AT THANKSGIVING TOMORROW
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Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
$36 400
Step-by-step explanation:
Step 1
The first step is to figure out how much money is saved at the end of each month for the period from January 1 to June 15. The amount deposited at the end of each month is obtained by multiplying the amount from the previous month by 3.
The amount deposited in January is
The amount deposited in February is
The amount deposited in March is
The amount deposited in April is
The amount deposited in May is
The amount deposited in June is
Step 2
The next step is to add up all the money that was deposited into the account. This calculation is shown below,
The length is twice its width:
Change to improper fraction:
Combine into single fraction:
Find Perimeter :