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bekas [8.4K]
3 years ago
10

A square garden is 12 feet long on each side. Janet needs to put a post at each corner. She also needs to put one every 3 feet o

n each side. How many posts does Janet need.
Mathematics
1 answer:
adelina 88 [10]3 years ago
4 0
12ft = 4 posts
4 x 4
=16 - 4
= 12
There is 4 post on each side but there is an overlap so you must take off 4 so there is no overlap
Therefore there are 12 posts
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A farmer plants twice as many acres of wheat as corn on his land. If he plants no more than 36 acres, what is the greatest numbe
Leona [35]

Answer: 12 acres could be planted (at most)

Step-by-step explanation: Since there will be twice as many acres of wheat in  comparison to the corn, out of the total 36 acres at least 24 of those will need to be wheat. That leaves 12 acres left for the corn.

6 0
3 years ago
How do I find the difference in the simplest form?
GrogVix [38]

Answer:

2

Step-by-step explanation:

\frac{8x}{4x - 7}  -  \frac{14}{4x - 7}  \\  \\  =  \frac{8x - 14}{4x - 7}  \\  \\  =  \frac{2 \cancel{(4x - 7)}}{\cancel{(4x - 7)}}  \\  \\  = 2

5 0
2 years ago
The seventh grade wants to break last year's record of 78 coats collected for the annual clothing drive. They have already colle
e-lub [12.9K]

Answer:

78=c-13

c=65

____________________

13                        65           78

3 0
3 years ago
on a large college campus, 84% of the students report drinking alcohol within the past month, 33% report using some type of toba
Natasha_Volkova [10]

Answer:  0.31

Step-by-step explanation:

Let A denotes the event that the students report drinking alcohol and B denotes the students report using some type of tobacco product .

Given : P(A) =0.84   ; P(B)=0.33    and        P(A∪B)=0.86

We know that P(A\cap B)=P(A)+P(B)-P(A\cup B)

Then, the probability that the student both drunk alcohol and used tobacco in the past month is given by :-

 P(A\cap B)=0.84+0.33-0.86=0.31

Hence, the probability that the student both drunk alcohol and used tobacco in the past month = 0.31

5 0
3 years ago
A brick is thrown upward from the top of a building at an angle of 250 above the horizontal, and with an initial speed of 15 m/s
mojhsa [17]

Answer:

(a) 25.08 m

(b) 2.05 m

Step-by-step explanation:

Let the height of the building be 'h'.

Given:

Angle of projection is, \theta=25°

Initial speed is, u=15\ m/s

Time of flight is, t=3.0\ s

(a)

Consider the vertical motion of the brick.

Vertical component of initial velocity is given as:

u_y=u\sin\theta\\\\u_y=15\sin(25)=6.34\ m/s

Vertical displacement of the brick is equal to the height of the building.

So, vertical displacement = -h (Negative sign implies downward motion)

Acceleration is due to gravity in the downward direction. So,

Acceleration is, g=-9.8\ m/s^2

Now, using the following equation of motion;

-h=u_yt+\frac{1}{2}gt^2\\-h=6.34(3)-\frac{9.8}{2}(3)^2\\\\-h=19.02-44.1\\\\-h=-25.08\\\\h=25.08\ m

Therefore, the building is 25.08 m tall.

(b)

Let the maximum height be 'H'.

At maximum height, the vertical component of velocity is 0 as the brick stops temporarily in the vertical direction.

So, v_y=0\ m/s

Now, using the following equation of motion, we have:

v_y^2=u_y^2+2gH\\\\0=(6.34)^2-2\times 9.8\times H\\\\19.6H=40.2\\\\H=\frac{40.2}{19.6}=2.05\ m

Therefore, the maximum height of the brick is 2.05 m.

5 0
3 years ago
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