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Luda [366]
3 years ago
15

List the first three multiples for 8

Mathematics
1 answer:
LekaFEV [45]3 years ago
6 0

Answer:

8,16,24,32

Step-by-step explanation:

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Quadrilateral ABCD ​ is inscribed in this circle.
Alecsey [184]
The sum of all interior angles in a polygon is

180(n-2), where n = sides, well, this is a QUADrilateral, so it has 4 sides, so the total is 360°.

now, let's find what angle C is first,

\bf \stackrel{A}{(2x-40)}+\stackrel{B}{(116)}+C+\stackrel{D}{(x)}=360\implies C+3x+76=360
\\\\\\
C+3x=284\implies C=284-3x

now, recall the "inscribed quadrilateral conjecture", where opposite angles are "supplementary angles", thus

\bf \stackrel{\measuredangle A}{(2x-40)}+\stackrel{\measuredangle C}{(284-3x)}=180\implies -x+244=180
\\\\\\
64=x\\\\
-------------------------------\\\\
\measuredangle A=2(64)-40
8 0
3 years ago
Read 2 more answers
Vicky records the low temperature for three consecutive days. Between the first and second days the temperature increased 6 degr
Sholpan [36]
<em>-9</em><span><em>º </em>

You can figure this out by doing every thing backwards:
</span> –6º plus 3 degrees the minus <span>6 degrees</span>
3 0
2 years ago
Read 2 more answers
Express this to single logarithm
zzz [600]

Answer:  \log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

  1. log(A) + log(B) = log(A*B)
  2. log(A) - log(B) = log(A/B)
  3. B*log(A) = log(A^B)

From there, we can then say the following:

\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}

8 0
2 years ago
Two towers make up the Vertical Forest. One is 76 meters tall, and the other is 111 meters tall. How many feet taller is the hig
prisoha [69]

Answer: 114.8

Step-by-step explanation: first multiply 76 times 3.28 (249.28) then multiply 11 by 3.28 (364.08) and subtract to get your awnser

6 0
2 years ago
Which piecewise function is shown in the graph?
mash [69]

Based on the characteristics of <em>linear</em> and <em>piecewise</em> functions, the <em>piecewise</em> function f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right. is shown in the graph attached herein. (Correct choice: A)

<h3>How to determine a piecewise function</h3>

In this question we have a graph formed by two different <em>linear</em> functions. <em>Linear</em> functions are polynomials with grade 1 and which are described by the following formula:

y = m · x + b     (1)

Where:

  • x - Independent variable.
  • y - Dependent variable.
  • m - Slope
  • b - Intercept

By direct observation and by applying (1) we have the following <em>piecewise</em> function:

f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right.

Based on the characteristics of <em>linear</em> and <em>piecewise</em> functions, the <em>piecewise</em> function f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right. is shown in the graph attached herein. (Correct choice: A)

To learn more on piecewise functions: brainly.com/question/12561612

#SPJ1

3 0
1 year ago
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