Answer:
The probability of Yarborough when you are randomly dealt 13 cards out of a well-shuffled deck of 52 card is 0.000547.
Step-by-step explanation:
The number of ways you can choose a set of 13 different cards from a deck of 52 cards is given by 52P13.
Hence the unordered sample space has 52P13 equally likely outcomes. The number of outcomes with no card above a nine is 32P13.
This leads to the same value for the desired probability of a Yarborough:
32P13 / 52P13 = 0.000547.
Answer:
the width is 0.7 feet
Step-by-step explanation:
Well we know that area = length * width. We know both the area and length, but not the width. Let's substitute the area and length in this equation, and substitute x for the width.
7 = 10 * x, or 7 = 10x
Now, solve for the width, or x, by dividing both sides by 10.
7(/10) = 10x(/10)
7/10 = x
Simplify 7/10 = 0.7
So the width of the banner is is 0.7 ft!
The formula is s = r * angle
Angle must be in RADIANS for the formula. Since the picture gives 135 degrees you either convert in the formula by adding the conversion factor, (s = r * angle * pi/180) or knowing that 135 degrees is 3pi/4.
s = 6 * 3* 3.14/4
s = 14.1
Answer:
The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Step-by-step explanation:
Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.
But,
<P = 048°
<Q =
- 
= 0
Sum of angles in a triangle = 
<P + <Q + <S = 
048° + 0
+ <S = 
+ <S = 
<S =
- 
= 
<S = 
Applying the Sine rule,
=
= 
= 
= 
= 
⇒ y = 
= 12.703
y = 12.70 km
= 
= 
= 
⇒ x = 
= 10.0475
x = 10.05 km
Thus,
the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Answer:
Step-by-step explanation:
The average car manufactured in the United states in 2001 could drive 24.5 miles on 1 car gallon of gas. To find the number of yards the car can travel on gallon of gas, we would convert 24.5 miles.
1 mile = 1760 yards
24.5 miles = 24.5 × 1760
= 43120 yards
Therefore, the car drives 43120 yards on 1 gallon of gas.