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AleksAgata [21]
3 years ago
11

What is 3x+y=-4? Hurry. I really need to know!

Mathematics
1 answer:
earnstyle [38]3 years ago
6 0
If you are solving for x : x= - y/3- 4/3

If u are solving for y: x= - y/3- 4/3
I apologize if i am wrong.
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A bridge hand in which there is no card higher than a nine is called a Yarborough. Specify an appropriate sample space and deter
Vilka [71]

Answer:

The probability of Yarborough when you are randomly dealt 13 cards out of a well-shuffled deck of 52 card is 0.000547.

Step-by-step explanation:

The number of ways you  can choose a set of 13 different cards from a deck of 52 cards is given by 52P13.

Hence the unordered sample space has 52P13 equally likely outcomes. The number of outcomes with no card above a nine is 32P13.

This leads to the same value for the desired probability of a Yarborough:

32P13 / 52P13  = 0.000547.

3 0
3 years ago
A banner has a length of 10 feet and an area of 7 square feet. What is the width of the banner?
const2013 [10]

Answer:

the width is 0.7 feet

Step-by-step explanation:

Well we know that area = length * width. We know both the area and length, but not the width. Let's substitute the area and length in this equation, and substitute x for the width.

 

7 = 10 * x, or 7 = 10x

 

Now, solve for the width, or x, by dividing both sides by 10.

 

7(/10) = 10x(/10)

 

7/10 = x

 

Simplify 7/10 = 0.7

So the width of the banner is is 0.7 ft!

6 0
4 years ago
Option D) 56.5<br> Please he I need to pass this unit test
galina1969 [7]
The formula is s = r * angle
Angle must be in RADIANS for the formula. Since the picture gives 135 degrees you either convert in the formula by adding the conversion factor, (s = r * angle * pi/180) or knowing that 135 degrees is 3pi/4.
s = 6 * 3* 3.14/4
s = 14.1
4 0
3 years ago
6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP
adelina 88 [10]

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = 360^{o} - 324^{o}

     = 036^{o}

Sum of angles in a triangle = 180^{o}

<P + <Q + <S = 180^{o}

048° + 036^{o} + <S = 180^{o}

84^{o} + <S = 180^{o}

<S  = 180^{o} -  84^{o}

    = 96^{o}

<S = 96^{o}

Applying the Sine rule,

\frac{y}{Sin P} = \frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{y}{Sin P} = \frac{z}{Sin S}

\frac{y}{Sin 48^{o} } = \frac{17}{Sin 96^{o} }

\frac{y}{0.74314} = \frac{17}{0.99452}

⇒ y = \frac{12.63338}{0.99452}

       = 12.703

y = 12.70 km

\frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{x}{Sin 36^{o} } = \frac{17}{Sin 96^{o} }

\frac{x}{0.58779} = \frac{17}{0.99452}

⇒ x = \frac{9.992430}{0.99452}

      = 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

6 0
3 years ago
The average car manufactured in the United states in 2001 could drive 24.5 miles on 1 car gallon of gas. Explain how to find the
bogdanovich [222]

Answer:

Step-by-step explanation:

The average car manufactured in the United states in 2001 could drive 24.5 miles on 1 car gallon of gas. To find the number of yards the car can travel on gallon of gas, we would convert 24.5 miles.

1 mile = 1760 yards

24.5 miles = 24.5 × 1760

= 43120 yards

Therefore, the car drives 43120 yards on 1 gallon of gas.

7 0
3 years ago
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